EXERCISE
MEAN, STANDARD DEVIATION,
AND 95% AND 99% OF THE
NORMAL CURVE
STATISTICAL TECHNIQUE IN REVIEW
Mean (X) is a measure of central tendency and is the sum of the raw scores divided by the number of scores being summed. Standard deviation (SD) is calculated to measure dispersion or the spread of scores from the mean (Burns & Grove, 2007). The larger the value of the standard deviation for study variables, the greater the dispersion or variability of the scores for the variable in a distribution. (See Exercise 16 for a detailed discussion of mean and standard deviation.)
Since the theoretical normal curve is symmetrical and unimodal, the mean, median, and mode are equal in the normal curve (see Figure 18-1). In the normal
…show more content…
In this example, 490 + 1.96 (100) = 686, and 490 - 1.96 (100) = 294. Thus 95% of scores lie between 294 and 686, expressed as (294, 686). Since 95% of the scores are between 294 and
686, this leaves 5% of the scores outside this interval. Since a normal curve is symmetric, one-half of the scores, or 2.5%, are at each end of this distribution.
To find where 99% of scores lie,Z ± 2.58 (SD), where 490 + 2.58 (100) = 748 and 490 - 2.58 (100) = 232.
Thus, 99% of the SAT scores lie between 232 and 748, which is expressed as (232, 748). Since the distribution of these scores is normal, 99% of the scores are between 232 and 748 and 0.5% of the scores are at each end of this distribution.
FIGURE 18-2 'ft Distribution of SAT Scores
SD=100
x = 490
Mean
RESEARCH ARTICLE
Source: Corless, I. B., Nicholas, P. K., McGibbon, C. A., & Wilson, C, (2004). Weight change, body image, and quality of life in HIV disease: A pilot study. Applied Nursing Research 77(4), 292-6.
Introduction
The purpose of this pilot study [conducted by Corless and colleagues (2004)] was to investigate the relationships of weight change, body image, length of time with HIV/AIDS diagnosis, and quality of life in individuals with HIV disease (Corless et al., 2004, p. 292). The sample consisted of 40 subjects: 23 men and 17 women. The HIV-positive adults in a primary care clinic were asked to participate, so this study has a sample of
7. Among freshmen at a certain university, scores on the Math SAT followed the normal curve, with an average of 550 and an SD of 100.
The area under the curve to the left of the unknown quantity must be 0.7 (70%). So, we must first find the z value that cuts off an area of 0.7 in the left tail of standard normal distribution. Using the cumulative probability table, we see that z=0.53.
Standard deviation is important in comparing two different sets of data that has the same mean score. One standard deviation may be small (1.85), where the other standard deviation score could be quite large (10)(Rumsey,
2. In order to determine the average amount spent in November on Amazon.com a random sample of 144 Amazon accounts were selected. The sample mean amount spent in November was $250 with a standard deviation of $25. Assuming that the population standard deviation is unknown, what is a 95% confidence interval for the population mean amount spent on Amazon.com in November?
2. Compute the means for the following set of scores saved as Ch. 2 Data Set 3 using IBM® SPSS® software. Print out a copy of the output. (Please refer to attachment)
An intelligence test for which the scores are normally distributed has a mean of 100 and a standard deviation of 15. Use this information to describe how the scores are distributed.
But why below 70? This score has been chosen as a result of normal distribution, meaning that it is directly linked and
2. For the following set of scores, fill in the cells. The mean is 74.13 and the standard deviation is 9.98.
Mean would be the most appropriate measure of central tendency to describe this data. This is because the mean is the average of all scores in the data set. If Dr. Williams were to graph the data into a bell shaped distribution, then the mean would be in the center where most of the scores are located. The mean is calculated using all information of the data set, and is the best score to use if you want to predict an individual score.
Based on the given sample of student test scores of 50, 60, 74, 83, 83, 90, 90, 92, and 95 after rearranging them from least to greatest. As the mean is based on the average of sum, the average of this sample is 79.67 or 80. The mode refers to numbers that appear the most in a sequence and in this case 83 and 90 both appear twice. Range calculates the difference between the largest and smallest number, which are 95 and 50 which have a difference of 45. The variance is the difference between the sum of squares divided by the sample size, which is the number in the sample minus one (Hansen & Myers, 2012), meaning it takes each number of the set and subtracts
NOTE: Project problems should not be posted to the Discussion threads. Questions on the project problems should be addressed to the instructor by sending an email or by attending office hours.
Q3: What is total number of males with disability N, age_band of less than 55 and final result fail?
AIDS, initially seen as a terminal illness, has transitioned to a chronic disease for those patients who are able to use antiretroviral therapy and despite the advancements in HIV therapies, around 15,000 to 16,000 persons still die from HIV in the United States each year. (Alexander, Back, & Collins, 2004, p. 5). These numbers are still low in comparison with the epidemic in the early years, but persons living with HIV still continue to experience pain, infections, and other physical and emotional symptoms that impact their life in a negative way forcing them to shift into less aggressive care (O'Neill, Selwyn, & Schientinger). Being a hospice case manager for over 4 years has given me the opportunity to take care of a few HIV patients that
The 95% confidence interval for the population mean is 66,438 to 80,241. This means that there is a 95% confidence that this interval has the population mean.
= IRR (normal) * 0.7 + IRR (best) * 0.2 + IRR (worst) * 0.1