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0.0239 mol of bismuth ( Mwt=209) is heated along with 0.0312 mol of sulfur (Mwt=32) to form Bi₂S3 (Mwt=514). At the end of reaction, the mass extracted and the free sulfur Bi₂S3 determine : (1) recovered is 16.36% of the total reactants mol feed. 2Bi + 3S the limiting reactant (2) the percent of excess reactant (3) the percent conversion of sulfur to Bi₂S3.

0.0239 mol of bismuth ( Mwt=209) is heated along with 0.0312 mol of sulfur (Mwt=32) to form Bi₂S3 (Mwt=514). At the end of reaction, the mass extracted and the free sulfur Bi₂S3 determine : (1) recovered is 16.36% of the total reactants mol feed. 2Bi + 3S the limiting reactant (2) the percent of excess reactant (3) the percent conversion of sulfur to Bi₂S3.

Introduction to Chemical Engineering Thermodynamics
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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0.0239 mol of bismuth ( Mwt=209) is heated along with 0.0312 mol of sulfur (Mwt=32) to form Bi₂S3 (Mwt-514). At the end of reaction, the mass extracted and the free sulfur recovered is 16.36% of the total reactants mol feed. 2Bi + 3S - Bi₂S3 determine : (1) the limiting reactant (2) the percent of excess reactant (3) the percent conversion of sulfur to Bi₂S3.
Transcribed Image Text:0.0239 mol of bismuth ( Mwt=209) is heated along with 0.0312 mol of sulfur (Mwt=32) to form Bi₂S3 (Mwt-514). At the end of reaction, the mass extracted and the free sulfur recovered is 16.36% of the total reactants mol feed. 2Bi + 3S - Bi₂S3 determine : (1) the limiting reactant (2) the percent of excess reactant (3) the percent conversion of sulfur to Bi₂S3.
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