1 2) Find the polynomial function with leading coefficient -5; degree 3; and -2,- A) f(x) = -5(x + 2)(5x - 1)(5x-7) C) f(x) = -1(x + 2)(5x - 1)(5x-7) A) f(x) = 4x4 - 17x³+x² -12 C) f(x) = 4x4 - 17x3+ 5x² +15x -5 3) Find the polynomial function with leading coefficient 4; degree 4; and -4, -1, 0, and 200- /100+ and 5 7 5 + X as zeros. the graph to guess possible linear factors of f(x). Then completely factor f(x) with the aid of syn 4) f(x) = 7x3 - 39x2 - 40x + 132 1 B) f(x) = -(x + 2)(5x - 1)(5x+7) D) f(x) = -(x + 2)(5x - 1)(5x-7) B) f(x) = 4x4 + 11x3-8x²-16x f(x) = 4x4 + 17x³ + x² -12x 3 as zer

College Algebra
10th Edition
ISBN:9781337282291
Author:Ron Larson
Publisher:Ron Larson
Chapter5: Exponential And Logarithmic Functions
Section: Chapter Questions
Problem 10CT
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Question
1
2) Find the polynomial function with leading coefficient -5; degree 3; and -2,
A) f(x) = -5(x + 2)(5x - 1)(5x-7)
C) f(x) = -1(x + 2)(5x - 1)(5x-7)
A) f(x) = 4x4 - 17x³ + x² -12
C) f(x) = 4x4 - 17x3+ 5x² +
-5
200-
3) Find the polynomial function with leading coefficient 4; degree 4; and -4, -1, 0, and
1³/14
/100+
+15x
-100
and
5
7
5
X
as zeros.
Use the graph to guess possible linear factors of f(x). Then completely factor f(x) with the aid of synthetic
4) f(x) = 7x3 - 39x² − 40x + 132
1
B) f(x) = (x+2)(5x - 1)(5x+7)
1
D) f(x) = -(x + 2)(5x - 1)(5x - 7)
B) f(x) = 4x4 + 11x³-8x²-16x
D)f(x) = 4x4 + 17x³ + x² -12x
as zeros.
Transcribed Image Text:1 2) Find the polynomial function with leading coefficient -5; degree 3; and -2, A) f(x) = -5(x + 2)(5x - 1)(5x-7) C) f(x) = -1(x + 2)(5x - 1)(5x-7) A) f(x) = 4x4 - 17x³ + x² -12 C) f(x) = 4x4 - 17x3+ 5x² + -5 200- 3) Find the polynomial function with leading coefficient 4; degree 4; and -4, -1, 0, and 1³/14 /100+ +15x -100 and 5 7 5 X as zeros. Use the graph to guess possible linear factors of f(x). Then completely factor f(x) with the aid of synthetic 4) f(x) = 7x3 - 39x² − 40x + 132 1 B) f(x) = (x+2)(5x - 1)(5x+7) 1 D) f(x) = -(x + 2)(5x - 1)(5x - 7) B) f(x) = 4x4 + 11x³-8x²-16x D)f(x) = 4x4 + 17x³ + x² -12x as zeros.
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