Find the algorithm time complexity and write type recurrence relation. RunO DebugI StopE Share A sSave{} BeautifyOnlineGDB betamain.pyonline compiler and debugger for c/c++1- def getLongestSeq(a, n):maxIdx = 0maxLen = 0currLen = 0currIdx = 0for k in range (n):if a[k] < 0:code. compile. run. debug. share.34IDEMy Projects7-Classroom new8currLen +=1Learn Programming10# New sequence, store# beginning index.if currlen == 1:currIdx = kProgramming Questions11Sign Up12-13Login14 -else:if currLen > maxLen:maxLen = currLenmaxIdx = currIdxcurrLen = 015-fy+ 24.8K1617181920-if maxlen > 0:21print(a[maxIdx:maxIdx maxLen])22-else:23print("No negative sequence detected.")2425 arr=list(map(int, input().split(" ")))26 n = len(arr)27 getLongestSeq(arr, n)input1 -1 -2 -1 3 -4 -5[-1, -2, -1]...Program finished with exit code 0Press ENTER to exit consoleAbout · FAQ • Blog • Terms of Use · Contact Us • GDB Tutorial •Credits · Privacy© 2016 - 2022 GDB Online

In the above code only one loop is used to find the longest negative consecutive subsequence. In…

1- def getLongestSeq(a, n): maxIdx = 0 maxLen = 0 currlen = e currIdx = 0 for k in range(n): if a[k] < ®: currlen +=1 3. 4 5 6 8 9. # New sequence, store # beginning index. if currlen == 1: currIdx = k 1 2 3 else: if currLen > maxLen: maxLen = currLen maxIdx = currIdx currLen = 0 4 5 9. if maxlen > 0: print(a[maxIdx:maxIdx maxLen]) else: 2 3\ print("No negative sequence detected.") 4 5 arr=list(map(int,input().split(" "))) 6 n len(arr) 7 getlongestSeq(arr, n)

1- def getLongestSeq(a, n): maxIdx = 0 maxLen = 0 currlen = e currIdx = 0 for k in range(n): if a[k] < ®: currlen +=1 3. 4 5 6 8 9. # New sequence, store # beginning index. if currlen == 1: currIdx = k 1 2 3 else: if currLen > maxLen: maxLen = currLen maxIdx = currIdx currLen = 0 4 5 9. if maxlen > 0: print(a[maxIdx:maxIdx maxLen]) else: 2 3\ print("No negative sequence detected.") 4 5 arr=list(map(int,input().split(" "))) 6 n len(arr) 7 getlongestSeq(arr, n)

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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