1. 1 (aq) + OCI (ag) CF (aq) + Of(aq)

Principles of Modern Chemistry
8th Edition
ISBN:9781305079113
Author:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler
Publisher:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler
Chapter17: Electrochemistry
Section: Chapter Questions
Problem 77AP
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Activity 4.1.1. Reaction time! Write the rate expressions for the following
reactions in terms of the disappearance of the reactants and the appearance
of the products:
1. 1(ag) + OCI (ag)
→
CF (aq) + Or(aq)
2. 4 NH3(g) +5 O2(g)
4 NO(g) + 6H20(g)
3. CH4(g) + Br2(g)
CH3BR(g) + HBr(g)
2.
Transcribed Image Text:Activity 4.1.1. Reaction time! Write the rate expressions for the following reactions in terms of the disappearance of the reactants and the appearance of the products: 1. 1(ag) + OCI (ag) → CF (aq) + Or(aq) 2. 4 NH3(g) +5 O2(g) 4 NO(g) + 6H20(g) 3. CH4(g) + Br2(g) CH3BR(g) + HBr(g) 2.
What's More
Activity 3.3.2. Solve me! Calculate the problem using Nernst equation. Show your solution.
Problem: In a test of a new reference electrode, a chemist constructs a voltaic cell consisting
of a Zn | Zn2+ half-cell and an H2 | H* half-cell under the following conditions:
[Zn2+] = 0.010 M
[H*] = 2.5 M
PH2 = 0.30 atm
Calculate Ecell at 298.15 K.
Transcribed Image Text:What's More Activity 3.3.2. Solve me! Calculate the problem using Nernst equation. Show your solution. Problem: In a test of a new reference electrode, a chemist constructs a voltaic cell consisting of a Zn | Zn2+ half-cell and an H2 | H* half-cell under the following conditions: [Zn2+] = 0.010 M [H*] = 2.5 M PH2 = 0.30 atm Calculate Ecell at 298.15 K.
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