1. A rectangular beam has b = 300mm, d = 500mm, As = 6 - 36mm diameter bars, fc' = 28.6 MPa, fy = 414 MPa. Calculate: a) depth of compression block, "a" b) fs c) + d) Mu
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- 500 mm 62.5 mm 375 mm 62.5 mm P. Determine the total required number of 20mm bars to be used in two end faces only for the 300mm x 500mm rectangular column shown to support the following loads: Pu = 800 kN Mu = 120 kN-m Use f'c = 20.7 MPa and fy = 413.7 MPa Use 1 ksi = 6.893 MPa %3D 300 mm O O O OFill in the blanks: For the given properties of the beam below, determine the safest wy that the beam will carry. bf = 850mm bw = 400mm tf = 100mm d = 400mm d' = 100mm fc' = 32MPA fy = 400MPA As = 8-32mm bars %3D The answer is kN/m Pu = 20 KN bf 3Pu O-50 Pu 1m As A 13 + bw + CS Scanned with CamScanner6₁ 20ft P= 20K CA Mmax= A max =
- For the given properties of the beam below, determine the safest wy that the beam will carry. bf = 850mm bw = 400mm tf = 100mm d = 400mm ニ d' = 100mm fc' = 32MPA %3D fy = 400MPA As = 8 - 32mm bars ニ The answer is kN/m Pu = 20 KN %3D bf 3Pu O-50 Pu 七キ Wu 5m As 13 + bw *SITUATION 1 Built-up column 10m long consists of W350X90 with two plates welded to form a box section with respect to x axis. The column is fixed at the bottom and pin-connected at the top, y-axis is braced at mid height. A = 11,540mm² y = 2.66 × 10ºmm* ly = 0.44 × 10°mm* b, = 250mm tw = 10mm ty = 16mm F, = 248 MPa a. Compute the effective slenderness ratio with respect to x-axis b. Compute the effective slenderness ratio with respect to y-axis c. Compute the Factor of Safety d. Compute the allowable stre ss e. Compute the load capacity of the columnHow Determin # As for the beam show in figre (including self weight) (P=35 M²-i fy=420) well kN/m WL=24 K~/3 590 250 5m
- in simply supported beam shown in fiy. use: Pey- loe sin 4t Yes-4-) %3D Pet) %3D m = 50 per unit length C = 150 EI=65 l0 IL.in? L/2 L/2Design a simply supported rectangular reinforced concrete beam. Note: The self-weight of the beam is not included. 6OKN 6kN/m Wa (LL) 650mm 2 m 7.25m b 350mm L bar dia =20 No. Of layers =two Fc mpa=25 Fy mpa =350For the given properties of the beam below, determine the safest wy that the beam will carry. bf = 850mm bw = 400mm tf = 100mm d = 400mm d' = 100mm fc' = 32MPa fy: 400MPa As = 8-32mm bars The answer is kN/m = 1m A Pu = 20 KN 3Pu Wu 5m 0.50 Pu ff ym 1B3 d bf As + bw-t + 1 tf 1
- ... Determine whether the D = 560 kips L = 68 kips compression member shown is adequate to support the given service loads. Take note Pu = 1.4D. 20' W12 × 79 K= 0.80, r= 3.05 in E = 29000 ksi, Fy = 50 ksi %3D A992 steel %3D Input Yes or No for your final answer. Note: Ag = 23.2 in^2 Blank 1 Blank 1 Add your answerQ2/ For the 60m simply supported beam having fc-30MPa and fy=420MP, calculate the immediate deflection due to dead load. As shown in figure below the service dead load on beam, not including own weigh: 250kN and service live load=-150kN. Take d-492mm. D.L=250KN LL-150KN 0.55m As 500mm 2 A=(³-20x²+x²) 2.00m 2.00m 6.00m 11 2.00m C.35m i ---For the given properties of the beam below, determine the safest wy that the beam will carry. bf = 800mm bw = 500mm tf = 90mm d = 375mm d' = 100mm fc' = 34.5MPa fy = 400MPa As = 8-32mm bars The answer is kN/m bf + A, D +bw t f Wu A को + Pu 50 5m KN (Factored) load B +im+