Answer all 1. Determine the number of significant digits in each of the following numbers.a. 6.521 gramsd. 2500 ma. 14.5+8+26.37 =c. 2.36+3.32 +0.375 +1.06 =Significant Figures Worksheetc. 17.57-6.2=2. Calculate answers to the following problems to the correct number of significant figures.c. 2.36 x 3.3 x 0.375 x 1.06 =b. 0.159 kme. 0.070080 cma. 0.000033. Calculate answers to the following problems to the correct number of significant figures.a. 23.47 12.058 =b. 9.80-4.762 = _C.c. 8,367,000__7. Express the following numbers in standard notation.a. 4.5x1049.030E-5c. 20.0 mLb. 13.25 +10.50+ 9.6=4. Calculate answers to the following problems to the correct number of significant figures.a. 2.6 x 3.78 =b. 13.25 x 10.50 x 9.6 =f. 25 rubiesd. 250+ 76.2 =d. 250 -76.2 =5. Calculate answers to the following problems to the correct number of significant figures..a. 35/0.62 =b. 39.25/10.50 = -_-_(c. 30.07g/0.106mL =6. Express the following numbers in scientific notation.d. 0.085 x 0.050 x 0.655 =b. 55,000,000d. 1.055g/0.0067mol =d. 0.02050b. 5.62E3

Significant figures are the digits of a number that are meaningful in terms of accuracy or…

1. Determine the number of significant digits in each of the following numbers. a. 6.521 grams d. 2500 m a. 14.5+8+26.37= c. 2.36+3.32 +0.375 +1.06= b. 0.159 km e. 0.070080 cm 2. Calculate answers to the following problems to the correct number of significant figures. c. 17.57-6.2= c. 20.0 mL f. 25 rubies b. 13.25 +10.50 +9.6= d. 250 + 76.2 = 3. Calculate answers to the following problems to the correct number of significant figures. a. 23.47 12.058 = b. 9.80-4.762=_ d. 250-76.2 = -

1. Determine the number of significant digits in each of the following numbers. a. 6.521 grams d. 2500 m a. 14.5+8+26.37= c. 2.36+3.32 +0.375 +1.06= b. 0.159 km e. 0.070080 cm 2. Calculate answers to the following problems to the correct number of significant figures. c. 17.57-6.2= c. 20.0 mL f. 25 rubies b. 13.25 +10.50 +9.6= d. 250 + 76.2 = 3. Calculate answers to the following problems to the correct number of significant figures. a. 23.47 12.058 = b. 9.80-4.762=_ d. 250-76.2 = -

Introductory Chemistry: A Foundation

9th Edition

ISBN:9781337399425

Author:Steven S. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Donald J. DeCoste

Chapter3: Matter

Section: Chapter Questions

Problem 9CR

See similar textbooks

Similar questions

The GPS in my car indicates that t have 100. mi left until I reach my destination. What is this distance in kilometers?
digits when measurements are multiplied o... Multiply or divide the following measurements. Be sure each answer you enter contains the correct number of significant digits. 7.81 x 0.6 mL =g ml. mol 846.32 mol + 0.29 L %3D L. mol x 15. L L. = |mol 78.1
III. Perform these calculations and express the result with the proper number of significant figures. a. (4.850 g – 2.34 g)/1.3 mL b. (4.66 x 10-3) × 4.666 c. 0.003400/65.2
2. Calculate the volume of 435 g block of copper. d=m =V=Mv =H359 8.939lcm3 48.712 3D 5. A rectangular block of lead has a mass of 1523 g. Calculate the height of the block if the length is 4.15 cm and the width is 3.75 cm. An nickel ore weighing 85.245 g was placed in a flask having a volume of 45.25 mL. The flask with the nickel ore was then filled with water and weighed. The nickel ore and the water weighed 113.571 g. The density of water is 0.9976 g/mL. Calculate the
3. Provide the answer with the appropriate number of significant figures. a. 6.03 x 650 b. 2.7 x 1031.645 c. 3.000 + 7.61 + 124.2 d. (3.55 x 109) x (9.5 x 10-7) e. 7.845 - 1.20 f. 7.845- 1.2 g. (6.72 x 106 ) - (4.32 x 10“ )
3. A method of analysis yields masses of gold that are low by 0.4 mg. Calculate the percent relative error caused by this result if the mass of gold in the sample is a. 500 mg b. 250 mg c. 60 mg 4. The method described above is to be used for the analysis of ores that assay about 1.2% gold. What minimum sample mass should be taken if the relative error resulting from a 0.4-mg loss is not to exceed a. -0.1% b. -0.8%
2. Do the following calculations and use the correct number of significant figures in your answers. Assume all numbers are the results of measurements. a. 0.208 + 4.9 + 1.11 b. 228 + 0.999 + 1.02 c. 8.543 − 7.954 d.(3.2 × 10−2) + (5.5 × 10−1) (hint: Write in the decimal form first, then add.) e. 336.86 − 309.11 f. 21.66 − 0.02387
I keep getting this wrong and have gone over the problem 6 times and cant figure out what im doing wrong. I thought the answer was 3.125 Calculate 5.1234 + 0.033 ÷ 1.650 and report to the correct number of significant figures. a. 5.143 b. 3.125 c. 5.1 d. 3.1
b. Perform each calculation to the correct number of significant figures i 89.3 x 77.0 x 0.08 ii. (568.99-232.1) + 5.3 iii. (3.14 x 2.4367)-2.34 IV. 1459.3 +9.77 +4.32 3. Unit Conversions and Dimensional Analysis a. Perform each conversion (maintain sig figs): i. 2491.6 g to kg ii. 248 cm to mm iii. 6781 mL wi iv. 78.3 in to cm
34. Convert 4.58 x 10³ cm³ to each unit. a. L b. mL c. gal d. qt The m in the equation for density is in italic type, meaning that it stands for mass rather than for meters. In general, the symbols for units such as meters (m), seconds (s), or kelvins (K) appear in regular type, while those for variables such as mass (m), volume (V), and time (t) appear in italics.
1. The radius of a potassium atom is 0.227 nm. Express this radius in the unit centimeters. 2. The diameter of Earth is 1.3 x 104 k. What is the diameter expressed in decimeters?
22.1 kg Fe (NO3) 2 Express your answer to three significant figures and include the appropriate units. e (Page) section 3 ecules or formula HA ? NFe(NO3)2 Value Units 0.7288 g C§H18 Express your answer to four significant figures and include the appropriate units. HA Value Units nC;H, = Part D