1. During glycolysis, a six carbon glucose molecule is broken down into 2 three carbon molecules of During this process, high energy electrons from glucose are transferred to 2 molecules. In addition, energy released during glucose breakdown powers formation of 2 molecules.
Q: 1. What are 3 steps are different in gluconeogenesis compared to glycolysis? Why are these steps…
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A: (Note: According to guidelines, we are supposed to answer only three subparts. Please repost other…
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Q: 1. In glycolysis, which of the following is true about oxidation of two glucose molecules to…
A: As Per Bartleby Guidelines , For Further Answers Please Repost The Question. Introduction :…
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A: Since you have posted multiple questions, we will solve the first question for you. If you want any…
Q: Why is the TCA cycle the central pathway of metabolism of the cell? Explain TCA cycle in your own…
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A: Note: For remaining answers please Repost The Question. Introduction: The process of breakdown of…
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Q: 2. Why are some enzymes needed only in the gluconeogenesis pathway and not in the glycolysis…
A: Hi! As you have posted multiple questions, I will be answering the first question for you. If you…
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A: (1) ATP has three phosphate groups and ADP has two phosphate groups. The correct option is C.
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- After the citric acid cycle reactions run _________, one six-carbon glucose molecule has been completely broken down to CO2. a. once b. twice c. six times d. twelve times2. During glycolysis, glucose is converted to pyruvate. Pyruvate then is converted to Acetyl coA and enters the citric acid cycle. Per one (1) glucose molecule that undergoes glycolysis and TCA cycle, complete the table below Equivalence in ATP Products from glycolysis 1. ATP 2. NADH 3. Pyruvate Products from TCA 4. NADH 5. FADH2 6. GTP TOTAL ATP Produced ATPS Equivalence in ATP ATPS ATPS ATPS ATPs produced ATP ATP = ATPs produced ATP ATP ATP 7._ATP2. During glycolysis, glucose is converted to pyruvate. Pyruvate then is converted to Acetyl coA and enters the citric acid cycle. Per one (1) glucose molecule that undergoes glycolysis and TCA cycle, complete the table below Equivalence in ATP Products from glycolysis 1. ATP 2. _NADH Pyruvate ATP: produced ATP АТР ATPS 3. ATPS produced АТР АТР Products from TCA Equivalence in ATP NADH 5. _FADH2 6. GTP 4. ATPS ATPS ATPS АТР TOTAL ATP Produced 7. ATP
- 1. Put together the sequence of components (numbers) that form the glycolysis pathway and the linked reaction. Choose the sequence from the following metabolites. Also mention the step in which NADH/FADH2 is formed along with the number. > Acetyl Co.A > Glucose. > Pyruvate. Fructose – 1, 6-bisphosphate > Glucose – 6 – phosphate. > Phosphoenol – pyruvate. > 1, 3 – Bisphosphoglycerate. > Glyceraldehyde 3-phosphate Fructose – 6 – phosphate > Glycerol 2-phosphate /2-phosphoglycerate. > Dihydroacetone – phosphate. > Glycerol – 3 – phosphate / 3- phosphoglycerate.11. Following glycolysis and the citric acid cycle, but before the electron transport chain and oxidative phosphorylation, the carbon skeleton of glucose has been broken down to CO2 with some net gain of ATP. Most of the energy from the original glucose molecule at that point in the process, however, is in the form of (LS1-7) * Glucose Glycolysis High Energy Molecules in Glycolysis and the Citric Acid Cycle 000000 in out 2 NAD+ 2 ATP 4 ADP 2 NADH 2 ADP 2 ATP Glycolysis Pyruvate 2 Pyruvates from 1 Glucose Molecule 2 ADP 2 ATP ,CO2 000 COA NAD+ NADH H* COA Acetyl CoA 2 CO2 Pyruvate oxidation in out Citric acid cycle NAD+ NADH 3 NAD* 3 NADH 3 H+ Citric acid cycle in out 3 NAD* FAD 3 NADH FADH2 ATP FADH2" ADP FAD ATP ADP + Dept. Biol. Penn State C2004 acetyl-CoA glucose pyruvate NADH11. Following glycolysis and the citric acid cycle, but before the electron transport chain and oxidative phosphorylation, the carbon skeleton of glucose has been broken down to CO2 with some net gain of ATP. Most of the energy from the original glucose molecule at that point in the process, however, is in the form of (LS1-7) * Glucose Glycolysis High Energy Molecules in Glycolysis and the Citric Acid Cycle 000000 in out 2 NAD+ 2 ATP 4 ADP 2 NADH Glycolysis 2 ADP 2 ATP Pyruvate 2 Pyruvates from 1 Glucose Molecule 2 ADP 2 ATP CO2 O00 COA NAD+ NADH H+ COA Acetyl CoA 2 CO2 Pyruvate oxidation 00 in out Citric acid cycle NAD+ NADH 3 NAD+ 3 NADH 3 H* Citric acid cycle in out 3 NAD* 3 NADH FAD ADP FADH2 АТР FADH2 FAD ATP ADP + P Dept. Biol. Penn State ©2004 acetyl-CoA glucose pyruvate NADH
- 1.. The sugar that occupies a central position in the metabolism of plants, animals and many microorganisms. 2. This enzyme is inhibited in the glycolytic pathway whenever the cell has ample ATP and is well supplied by other fuels such as fatty acids. 3. The enzyme that is only present in the liver and kidney during glycogen utilization. 4. The glycolytic substrate responsible for the entry of Mannose in the preparatory stage of glycolysis. 5. What is the pathway involved during the lipid utilization into glucose in plants?The first step of glycolysis, conversion of glucose to glucose-6-phosphate (Choose all that apply) O is a phosphorylation reaction O results in the cleavage of a phosphoanhydride bond O prevents glucose from diffusing back out to the cell via a glucose GLUT transporter O results in a phosphoryl group transfer from fructose 1,6 bisphosphate O is an aldose isomerization reaction O results in the formation of a thioester bond1. Put together the sequence of components (numbers) that form the glycolysis pathway and the linked reaction. Choose the sequence from the following metabolites. Also mention the step in which NADH/FADH; is formed along with the number. > Acetyl ÇoA > Glucose. > Pyruvate. > Fructose – 1, 6-bisphosphate > Glucose – 6- phosphate. > Phosphoenol – pyruvate. > 1,3– Bisphosphoglycerate. > Glyceraldehyde 3-phosphate Fructose – 6– phosphate > Glycerol 2-phosphate /2-phosphoglycerate. Dihydroacetone – phosphate.
- e 5: The third step of the pathway glycolysis is made up of the two following reactions. i. Fructose-6-phosphate + Pi Fructose 1,6 bisphosphate + H₂O 4Gº' = +16.3 kJ/mol ATP_____+ H₂O → ADP Pi AGO¹ = 30.5 kJ/mol What would be the AGO' for the production of Fructose-6-P and ATP? OAGO' = - 30.5 kJ/mol AGO' AGO' = + 16.3 kJ/mol AGO'= - 14.2 kJ/mol AGO' = 46.8 kJ/mol None of the given answers.2.Assume we start with 1 Glucose molecule. What are the inputs to the payoff phase of glycolysis? a. 2xPyruvate b. 2xGlyceraldehyde-3P c. 1xDihydoxyacetone-P and 1xGlyceraldehyde-3P d. 2xDihydroxyacetone-P1. The first step in the payoff phase of glycolysis is catalyzed by the enzyme glyceraldehyde 3-phosphate dehydrogenase, an enzyme that contains a nucleophilic cysteine playing a central role in the reaction. A) In the direction of gluconeogenesis, what reaction does this enzyme catalyze? AG° = -6.3 kcal/mol for this reaction in the direction of gluconeogenesis. Based on what you know about the substrates involved, provide two chemical reasons as to why the AGO of this reaction is negative.