1. In an exothermic process, the volume of a system contracted from 3243 mL to 2087 mL against a constant pressure of 1.063 bar. During the process, 124.6 calories of heat energy were released. What was the internal energy change for the system in joules?

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Chapter6: Thermochemisty
Section: Chapter Questions
Problem 6.132QP
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PROBLEMS (1 L atm = 101.325 J, 1 L bar = 100.000 J)
1. In an exothermic process, the volume of a system contracted from 3243 mL to 2087 mL against a constant
pressure of 1.063 bar. During the process, 124.6 calories of heat energy were released. What was the internal
energy change for the system in joules?
2. Calculate the change in internal energy for the thermal decomposition of 5.432 g of potassium chlorate at a
constant external pressure of 1.634 bar. The decomposition reaction is
2KC1(s) + 3 O2(g)
Potassium chlorate's heat of formation is -391.20 kJ/mol, potassium chloride's heat of formation is -435.87
kJ/mol, and oxygen has a density of 1.308 g/L at the reaction temperature. Recall that the enthalpy of a reaction
can be determined by a summation of enthalpies of formation.
2 KC103 (5)
A
ΜΠΟΣ
Transcribed Image Text:PROBLEMS (1 L atm = 101.325 J, 1 L bar = 100.000 J) 1. In an exothermic process, the volume of a system contracted from 3243 mL to 2087 mL against a constant pressure of 1.063 bar. During the process, 124.6 calories of heat energy were released. What was the internal energy change for the system in joules? 2. Calculate the change in internal energy for the thermal decomposition of 5.432 g of potassium chlorate at a constant external pressure of 1.634 bar. The decomposition reaction is 2KC1(s) + 3 O2(g) Potassium chlorate's heat of formation is -391.20 kJ/mol, potassium chloride's heat of formation is -435.87 kJ/mol, and oxygen has a density of 1.308 g/L at the reaction temperature. Recall that the enthalpy of a reaction can be determined by a summation of enthalpies of formation. 2 KC103 (5) A ΜΠΟΣ
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