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1. Indicate the geometry of each carbon atom (i.e., linear, trigonal planar, tetrahedral) H :O: HH 1 S²N=3+0=3 Z 959 C C₁ T H H H 3+0=3 - trigonal = 3+0=3 = 4+0=4 = 4+0=4 = 4+0=4 2 = 4+0=4 = 4+0=4 - tetrahedral H H BH TH CH H 2. Use hybridization and orbitals to explain why some bonds above rotate freely and other bonds do not. Feel free to draw to explain your answer H → Sp² hybridization → Sp2-hybridization (trigonal) hybridization C3Sp2- C4 SP3 -hybridization Cz→ SP³ -hybridization Cos S.N=no. of bond + no. of won ar Lone POL Cs→Sp3-hybridization tetrahedral Cu→Sp3-hybridization G→Sp³-hybridization

1. Indicate the geometry of each carbon atom (i.e., linear, trigonal planar, tetrahedral) H :O: HH 1 S²N=3+0=3 Z 959 C C₁ T H H H 3+0=3 - trigonal = 3+0=3 = 4+0=4 = 4+0=4 = 4+0=4 2 = 4+0=4 = 4+0=4 - tetrahedral H H BH TH CH H 2. Use hybridization and orbitals to explain why some bonds above rotate freely and other bonds do not. Feel free to draw to explain your answer H → Sp² hybridization → Sp2-hybridization (trigonal) hybridization C3Sp2- C4 SP3 -hybridization Cz→ SP³ -hybridization Cos S.N=no. of bond + no. of won ar Lone POL Cs→Sp3-hybridization tetrahedral Cu→Sp3-hybridization G→Sp³-hybridization

Chemistry: The Molecular Science
Chemistry: The Molecular Science
5th Edition
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:John W. Moore, Conrad L. Stanitski
Chapter7: Molecular Structures
Section: Chapter Questions
Problem 102QRT: There are two compounds with the molecular formula HN3. One is called hydrogen azide; the other is...
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Please explain no. 2 in deyail

1. Indicate the geometry of each carbon atom (i.e., linear, trigonal planar, tetrahedral). 디 C₁ S₁N=3+0=3 = 3+0=3 = 3+0=3 64 C = 4+0=4 =4+0=4 مرين сз H 8 HI Н H H:O: H9 H H -trigonal tetrahedral H HO? hybridization C3-> Sp2- C4 SP3 -hybridization 6H &H HOT H H₁ I I C₁ → Sp² hybridization C₂ Sp²-hybridization trig = 4+0=4 = 4+0=4 = 4+0=4 2. Use hybridization and orbitals to explain why some bonds above rotate freely and other bonds do not. Feel free to draw to explain your answer S.N=no. of bond + no. of Lone Pair Cs→Sp3-hybridization tetrahedral C-Sp3-hybridization G→SP³-hybridization. Cg → SP3 -hybridization 8
Transcribed Image Text:1. Indicate the geometry of each carbon atom (i.e., linear, trigonal planar, tetrahedral). 디 C₁ S₁N=3+0=3 = 3+0=3 = 3+0=3 64 C = 4+0=4 =4+0=4 مرين сз H 8 HI Н H H:O: H9 H H -trigonal tetrahedral H HO? hybridization C3-> Sp2- C4 SP3 -hybridization 6H &H HOT H H₁ I I C₁ → Sp² hybridization C₂ Sp²-hybridization trig = 4+0=4 = 4+0=4 = 4+0=4 2. Use hybridization and orbitals to explain why some bonds above rotate freely and other bonds do not. Feel free to draw to explain your answer S.N=no. of bond + no. of Lone Pair Cs→Sp3-hybridization tetrahedral C-Sp3-hybridization G→SP³-hybridization. Cg → SP3 -hybridization 8
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