1. You must prepare 250 ml of (0.1 mM EDTA, 2% w/v SDS, 40 mM NaCl) given 4.68% w/v NaCl (FW 58.44), 0.25 M EDTA, powdered SDS, water. Steps: a. How much 0.25M EDTA will you use? b. How much 4.68% w/v NaCl will you use? c. How much powdered SDS will you use?
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- A 0.5131-g sample containing KBr is dissolved in 50 mL distilled water. Titrating with 0.04614 M AgNO3 requires 25.13 mL to reach the Mohr endpoint. A blank titration requires 0.65 mL to reach the same endpoint. Report the % (w/w) KBr in the sample. [Ans. 26.19 % (w /w)]AaBbCcDdEe AaBbCcDc AaBbCcDdE AaBbCcDdF AaBb A v 三v Emphasis Heading 1 Normal Strong Sub PRE-LAB QUESTIONS 1. Calculate the molarity of a 6.15% (w/v%) sodium hypochlorite (NaOCI) solution. 2. Calculate the molarity of a solution of Erythrocin B (MW 879.9 g/mol) if a 0.5028-g sample is diluted to 100 mL in a volumetric flask and then two serial dilutions are carried out in which 5-mL aliquots are diluted to 100 mL using volumetric equipment. 3. Based on the table, what is the order of reaction for Red Dye #3 and bleach if the following graph gives a straight line: Order of m Straight Line Plot [Red Dye #3] vs time In[Red Dye #3] vs time 1/[Red Dye #3] vs time 1 ates) E Focus 目 MacBook Air2. A 0.5131-g sample containing KBr is dissolved in 50 mL of distilled water. Titrating with 0.04614 M AgNO3 requires 25.13 mL to reach the Mohr end point. A blank titration requires 0.65 mL to reach the same endpoint. Report the %w/w KBr in the sample.
- A water sample is approximated to have a total hardness equal to 120.0ppm. How many milliliters of 0.01000N EDTA will be needed to titrate 250.00mL of the said water sample?(MM CaCO3=100.09g/mol). ** Need asap pls. Thanks.A 0.5131-g sample that contains KBr (MM: 119.0023) is dissolved in 50 mL of distilled water. Titrating with 0.04614 M AgNO3 requires 25.13 mL to reach the Mohr end point. A blank titration requires 0.65 mL to reach the same end point. Report the %w/w KBr in the sample.DATA AND RESULTS: Titration Data (Standardization of EDTA) Example II Mass, g Caco, 0.0250 0.0251 0.0246 0.0254 Final reading, mL 25.00 24.91 24.87 25.31 Initial Reading, mL 0.00 0.02 0.02 0.02 Volume, mL EDTA 25.00 Molarity of EDTA, M 0.009992 B. Analysis Data Example II Volume of Sample, mL 25.00 24.90 25.10 25.0 Final reading, mL 27.46 25.08 25.06 24.99 Initial Reading, mL 0.00 0.02 0.02 0.02 Volume of EDTA, mL 27.46 Molarity of EDTA, M 0.009992 Ca" concentration, ppm 440 STATISTICAL EVALUATION OF RESULTS Standardization of EDTA Mean, M EDTA Median, M EDTA Standard Deviation Ci for u at 95% Prob. Level Reported value: M EDTA Ca" Concentration Mean, Ca" ppm Median, Ca" ppm Standard deviation Cl for u at 95% Prob. Level Reported value: Ca" ppm
- Titration of Ca2+ and Mg2+ in a 50.00 mL sample of hard water required 23.65 mL of 0.01205 M EDTA. A second 50.00 mL aliquot was made strongly basic solution. Calculate the ff: a. The total hardness of water sample b. Concentration in ppm CaCO3 in the sample c. Concentration in ppm MGCO3 in the sampleAspirin powder = 0.8110g MW of Aspirin = 180g.mol-1 Volume of 0.5N HCl consumed in back titration = 23.50mL Volume of 0.5N HCl consumed in blank titration = 44.50mL Percent purity (USP/NF) = Aspirin tablets contain NLT 90.0% and NMT 110.0% of the labeled amount of aspirin (C9H8O4) What is the calculated weight (in grams) of pure aspirin?..Procedure Preparation of Dilute Solution of Vinegar • Using a 10 mL pipette, transfer 10mL of vinegar into 100 mL volumetric flask. • Dilute to mark of the volumetric flask using distilled water. B. Titration of Diluted Solution of Vinegar • Transfer 25 mL of diluted solution to 250 mL Erlenmeyer flask. • Add 0.5 mL phenolphthalein indicator. Set aside. • Transfer 50mL of 0.110 M NaOH into a 50 mL burette. • Titrate the diluted solution until the phenolphthalein endpoint (very faint pink). • Record volume of NaOH used. Answer the question: What is the experimentally determined concentration of acetic acid in your vinegar solution: (Please give your answer to three significant figures.) ______ M Acetic Acid
- Standardization of EDTA was done using MgSO4 standard wherein a 50-mL aliquot of solution obtained from 0.480 g MgSO4 in 500 mL needed 39.4 mL of the EDTA solution to reach the endpoint. Determine how many milligrams of CaCO3 will react per mL of this EDTA solution.The molar absorptivity of KMNO, at 525 nm is 2.2-x 10° L mol"-cm'. What is the concentration of a solution made from KMNO4 that has an absorbance of 0.58 with a cell path length of 0.50 cm? A. 2.2 x 10' mol/L B. 1.3'x 10° mol/L C. 5.3-x 10“ mol/L D. 1.1-x 10° mol/L E. 2.3-x 10* mol/LA 0.3172 g sample containing only KCl (MM: 74.55)and NaBr (MM: 102.89) is dissolved in 50 mL water and titrated with 0.1120 M AgNO3, requiring 36.14 mL to reach the endpoint. What is the % NaBr in the sample?Note: Send to me your solution for perfect points with proper name and label. a. 17.40% b. None of the given choices c. 78.39% d. 15.22% e. 82.41%