1.876 g of the sample containing H2C2O4requires 38.84 mL of 0.1032 M of NaOH for titration: H2C2O4+ 2 NaOH →Na2C2O4+ 2 H2OA 1.38 mL of 0.0992 M HCl is used in the back –titration. (a)Calculate the percentage of H2C2O4in the sample.(b)Calculate the percentage expressed as the dihydrate, H2C2O4•2H2O.
1.876 g of the sample containing H2C2O4requires 38.84 mL of 0.1032 M of NaOH for titration: H2C2O4+ 2 NaOH →Na2C2O4+ 2 H2OA 1.38 mL of 0.0992 M HCl is used in the back –titration. (a)Calculate the percentage of H2C2O4in the sample.(b)Calculate the percentage expressed as the dihydrate, H2C2O4•2H2O.
Chapter14: Principles Of Neutralization Titrations
Section: Chapter Questions
Problem 14.38QAP
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1.876 g of the sample containing H2C2O4requires 38.84 mL of 0.1032 M of NaOH for titration: H2C2O4+ 2 NaOH →Na2C2O4+ 2 H2OA 1.38 mL of 0.0992 M HCl is used in the back –titration. (a)Calculate the percentage of H2C2O4in the sample.(b)Calculate the percentage expressed as the dihydrate, H2C2O4•2H2O.
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