[15] IP ADDRESS DECODING:IP: 139.182.148.50NM: 255.255.254.0128 64 3211 1NA: NETWORK ADDRESS16 81 1ORBA: BROADCAST ADDRESSAND 255.255.254.0 = 11111111.11111111.11111110.0000000010001010.10110110.10010100.00000000139. 182. 148. 0NA:41BA:2 111139.182.148.50=10001010.10110110.10010100.00110010139.182.148.50 = 10001010.10110110.10010100.00110010255.255.254.000000000.00000000.00000001.11111111PRACTICE: PLEASE CALCULATE[NA: Network Address] AND [BA: Broadcast Address]IP: 172.16.0.100● NM: 255.255.252.010001010.10110110.10010101.11111111139. 182. 149 . 255(First Address of the Network)(Last Address of the Network)

Computer networks enable devices to exchange data and resources, regardless of their physical…

[15] IP ADDRESS DECODING: IP: 139.182.148.50 NM: 255.255.254.0 128 64 32 1 1 1 NA: NETWORK ADDRESS 16 8 4 1 1 1 AND 255.255.254.0 = 11111111.11111111.11111110.00000000 10001010.10110110.10010100.00000000 139. 182. 148. 0 BA: BROADCAST ADDRESS 2 1 1 1 139.182.148.50=10001010.10110110.10010100.00110010 NA: BA: OR 255.255.254.0 = 00000000.00000000.00000001.11111111 10001010.10110110.10010101.11111111 139.182.148.50=10001010.10110110.10010100.00110010 139 182 PRACTICE: PLEASE CALCULATE [NA: Network Address] AND [BA: Broadcast Address] IP: 172.16.0.100 NM: 255.255.252.0 149 255 (First Address of the Network) (Last Address of the Network)

[15] IP ADDRESS DECODING: IP: 139.182.148.50 NM: 255.255.254.0 128 64 32 1 1 1 NA: NETWORK ADDRESS 16 8 4 1 1 1 AND 255.255.254.0 = 11111111.11111111.11111110.00000000 10001010.10110110.10010100.00000000 139. 182. 148. 0 BA: BROADCAST ADDRESS 2 1 1 1 139.182.148.50=10001010.10110110.10010100.00110010 NA: BA: OR 255.255.254.0 = 00000000.00000000.00000001.11111111 10001010.10110110.10010101.11111111 139.182.148.50=10001010.10110110.10010100.00110010 139 182 PRACTICE: PLEASE CALCULATE [NA: Network Address] AND [BA: Broadcast Address] IP: 172.16.0.100 NM: 255.255.252.0 149 255 (First Address of the Network) (Last Address of the Network)

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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