2 A debt of P75,000 is to be amortized by giving payment of r15,000 at the end of each quarter at 3% simple interest every quarter. Construct the amortization schedule. а. Amount Payment Number of Payment Payment on Interest Payment on Principal Balance b. How much of the third payment is allotted for the interest? c. How much of the third payment is allotted for the principal? d. How much is the balance after the third payment? How many payments are needed to settle the debt? е. f. How much is the concluding payment? g. Find the total interest to be paid.

2 A debt of P75,000 is to be amortized by giving payment of r15,000 at the end of each quarter at 3% simple interest every quarter. Construct the amortization schedule. а. Amount Payment Number of Payment Payment on Interest Payment on Principal Balance b. How much of the third payment is allotted for the interest? c. How much of the third payment is allotted for the principal? d. How much is the balance after the third payment? How many payments are needed to settle the debt? е. f. How much is the concluding payment? g. Find the total interest to be paid.

Essentials Of Investments

11th Edition

ISBN:9781260013924

Author:Bodie, Zvi, Kane, Alex, MARCUS, Alan J.

Publisher:Bodie, Zvi, Kane, Alex, MARCUS, Alan J.

Chapter1: Investments: Background And Issues

Section: Chapter Questions

Problem 1PS

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3. A debt of P3,500 is to be amortized by 6 equal semiannual payments with interest at 6%compounded semiannually. What is the total interest to be paid during the term of the loan?
The debt is amortized by the periodic payment shown. Compute (a) the number of payments required to amortize the debt; (b) the outstanding principal at the time indicated. Payment Interval Conversion Debt PrincipalDebt Payment $14,000 Outstanding Principal After: 7th payment Interest Rate Period $875 1 month 12% monthly (a) The number of payments required to amortize the debt is. (Round the final answer up to the nearest whole number. Round all intermediate values to six decimal places as needed.) (b) The outstanding principal is $. (Round the final answer to the nearest cent as needed. Round all intermediate values to six decimal places as needed.)
A loan is to be amortized by n level annual payments of X where n > 5. You are given (1) The amount of interest in the first payment is 604.00 (2) The amount of interest in the third payment is 593.75 (3) The amount of interest in the fifth payment is 582.45 Calculate X.
The debt is amortized by the periodic payment shown Compute (a) the number of payments required to amortize the debt, (b) the outstanding principal at the time indicated Debt PrincipalDebt Payment Payment Interval Conversion Period monthly Outstanding Principal After: 6th payment Interest Rate $16,000 $1,419 3 months 6% (a) The number of payments required to amortize the debt is Round up to the nearest integer.) (b) The outstanding principal is S (Round the final answer to the nearest cent as needed Round all intermediate values to six decimal places as needed).
. A debt of P3,500 is to be amortized by 6 equal semiannual payments with interest at 6%compounded semiannually. Find the periodic payment and construct on amortization schedule.
An amortization of a debt is in a form of a gradient series of ₱5,000 on the first year, ₱4,500 on the second year, ₱4,000 on the third year, ₱3,500 on the fourth year. Determine future amount of the amortization if interest is 5%. Ans. ₱18,449.37
The debt is amortized by the periodic payment shown Compute (a) the number of payments required to amortize the debt, (b) the outstanding principal at the time indicated Payment Interval 1 month Conversion Period quarterly Outstanding Principal After: dth payment Dobt Principal Debt Payment Interest Rate $17.000 $1.265 6% (a) The number of payments required to amortize the debt is (Round up to the nearest integer.) (b) The outstanding principal is s (Round the final answer to the nearest cent as needed Round all intermediate values to six decimal places as needed)
The debt is amortized by the periodic payment shown. Compute (a) the number of payments required to amortize the debt; (b) the outstanding principal at the time indicated. Debt Principal Debt Payment Payment Interest Rate Interval Conversion Period Outstanding Principal After: $14,000 $832 3 months 12% monthly 7th payment (a) The number of payments required to amortize the debt is 24 I (Round up to the nearest integer.) (b) The outstanding principal is $ (Round the final answer to the nearest cent as needed. Round all intermediate values to six decimal places as needed.)
Construct the amortization schedule for a $16,000.00 debt that is to be amortized in 12 equal semiannual payments at 6% interest per half-year on the unpaid balance. Fill out the amortization schedule below. Round all values to the nearest cent. Unpaid Balance Reduction Payment Number 0 Payment Interest Unpaid Balance $ C... ci, 1.
The debt is amortized by the periodic payment shown. Compute (a) the number of payments required to amortize the debt, (b) the outstanding principal at the time indicated. Outstanding Principal After: 6th payment Conversion Payment Interval Interest Rate Period Debt PrincipalDebt Payment $14.000 $893 3 months 9% quarterly (a) The number of payments required to amortize the debt is (Round the final answer up to the nearest whole number. Round all intermediate values to six decimal places as needed.) (b) The outstanding principal is $ (Round the final answer to the nearest cent as needed. Round all intermediate values to six decimal places as needed)
An amortization of a debt is in a form of a gradient series of P10,000 on the first year, P9,500 on the second year, P9,000 on the third year, P8,500 on the fourth year. Determine the future amount of the amortization if interest is 0.12.
7. Fill in the amortization schedule below for a $10,000 debt that is to be amortized in six equal semiannual payments at 6.3% interest compounded semiannually. Note that all entries in the table should be rounded to the nearest cent, and the final payment should be adjusted so that the ending balance is zero.

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