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- Which of the following statements regarding circuits are true? To find resistance in a parallel circuit, you must sum the individual resitances The direction of conventional current is the direction of positive charge flow. In a circuit, electrons flow from high potential energy (at the negative terminal) to low potential energy (at the positive terminal). When electricity is passed through a lightbulb, the electrons are 'used up' by the bulb. All voltages in a loop sum to 12V The current that flows into a resistor is the same as the current that flows out. To 'short circuit' something means there is an alternate path of less resistance for the current to flow. Switching on a light happens immediately because electrons move from the power source to the bulb incredibly quickly. A 'kilowatt-hour' is a unit of power, not energy.150 100 + VA- a -4V AVA -7V 81. B b Figure 2 shows a simplified model of a gas-discharge lamp. One characteristic of these lamps is that they exhibit negative resistance; in other words, as current increases the voltage drops further, making such lamps inherently unstable. As such, a current-limiting ballast is required. For the connection shown in the figure: 1. Find the equivalent Thevenin circuit of the lamp. 2. Find the ballast resistance needed to limit the current drawn from a 24-volt source to 6 amperes.the adjoining figure. This lamp can withstand a maximum voltage 3.0 v 0.4 9. Volt-ampere (V-I) charaeteristics of an incandescent lamp 16thd in and a maximum current 0.4 A. An infinite ladder network consisting a large number of these lamps is also shown in the figure given belo How much maximum voltage can be applied between the terminals A and B, so that no lamp gets damaged? (Use V5 = 2.2). Ans:x4.2V Hint: Curentin all bulls except first isWhich of the following statements are correct for the circuit below? Thanks to the capacitors I – C1 and C2, the voltage gain of the circuit increases. II – Capacitors C1 and C2 are coupling capacitors and provide an isolation function between AC and DC voltages in the circuit. Thanks to the III – RE resistor, the voltage gain of the circuit increases. Thanks to the IV – RE resistor, the stability of the circuit increases. The V – C3 Capacitor is a bypass capacitor and prevents the loss of voltage gain. Capacitor VI – C3 is a coupling capacitor and has no effect on the voltage gain in the circuit. VII – As the value of the source internal resistance Rs increases, the voltage gain decreases. VIII – The voltage gain decreases as the value of any RL load to be added to the circuit increasesThe diagram in the figure shows a simple circuit consisting of a battery and a load consisting of two resistors.The battery voltage is UB = 56 V and the value of the resistors is:R1 = 1800R2 = 5400a) The ammeters in the circuit show the following value:A1 shows valueA2 shows valueA3 shows valueb) In the load, the effect developsc) The total resistance of the load isUse Kirchhoff's Law to solve for the current passing through each resistor. Compare it with what you got from the PHET Simulation A D 392 www 6V E www F 192 www 292 352 www 9V B C%3D ) Drurde (l0o1102 and (oCircuits IShow you solution pleaseA lead wire and an iron wire are connected in parallel. Their respective specific resistances are in the ratio 49: 24. The former carries 80 percent more current than the latter and the latter is 47 percent longer than the former. Determine the ratio of their cross sectional areas ROUND OFF TO THE NEAREST HUNDRETHSSEE MORE QUESTIONS