2. Consider a four-input function that outputs a 1 whenever an even number of its inputs are 0. a) Construct the Truth Table b) Generate the K-map for the expression c) Find minimal sum-of-product and draw the circuit diagram. d) Draw the logic diagram
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- Problem: Derive the logic expressions for a circuit that compares two unsigned numbers: X = x2x1xo and Y = = y2y1yo and generates three outputs: XGY, XEY, and XLY. One of these outputs is set to 1 to indicate that X is greater than, equal to, or less than Y, respectively.Simplify the following expression using Karnaugh map and implement. Draw simplified logic diagram as well. Implement on Multisim software. (a) Y=A.B.C'.D+A.B'.C'.D+A'.B'.C'.D+A'.B.C'.D+A'.B'.C'.D'+A'.B.C'.D'+A'.B.C.D'+A'.B.C.D+A'.B'.C.DDetermine the simplified Sum of Product expression of Q1 and Q2 from the table using a K-Map, then draw the simplified logic diagram. SHOW KMAP WITH THE FINAL EXPRESSION & LOGIC DIAGRAM
- Using the analysis technique where you first extract the truth table and then use it to derive the output’s logic expression, analyze the circuit. Record your results below. I added the circuit as an image Conclusion In your own words, describe the process used to analyze a logic circuit where you first extract a truth table and then derive the logic expression. 2.Again, in your own words, describe the process used to analyze a logic circuit where you first extract the logic expression and then derive the truth table.1. Given the Boolean expression (b + d)(a’+ b’ + c),a. Convert the expression to the other standard form. What do you call this standard form?b. Derive its canonical form. What do you call this canonical form?c. Derive the other canonical form. What do you call this canonical form?d. Provide the truth table of the expressione. Draw the logic circuit diagrams of the 2 standard formsDirection: Analyze the given circuit and find the following: Logic Expression Simplified Logic Expression using Boolean Algebra Simplified Circuit
- A full adder takes three inputs, A, B, Cin, and produces two outputs, S, Cout. Explain the logic equation for the sum and carry-out bits. How can you implement this full adder using half adders?Consider the circuit below. The switches are controlled by logic variables such that, if A is high, switch A is closed, and if A is low, switch A is open. Conversely, if B is high, the switch labeled is open, and if B is low, the switch labeled is closed. The output variable is high if the output voltage is 5V, and the output variable is low if the output voltage is zero. a. Write a logic expression for the output variable. b. Construct the truth table for the circuit. A Logic 1 5V(+ B C Logic 0 RExcess-3 code is significant for arithmetic operations as it overcomes shortcoming encountered while using 8421 BCD code to add two decimal digits whose sum exceeds 9. Excess-3 arithmetic uses different algorithm than normal non-biased BCD or binary positional number system. An electronics company has hired your services to design a code converter that converts Binary Coded Decimal (BCD) code for it. Design the converter.
- A circuit has four inputs (A, B, C, D) and two outputs (X, Y). The output X is logically high if the decimal equivalent in input binary combination is odd number. The output Y is logically high if the decimal equivalent in input binary combination is divisible by 3. Find the minimum expression for the two outputs and draw the logic diagram?Introduction to Logic design EENG115 . Please solve it by introduction to Logic design onley and make your line clear and step by step please Please please make sure your answer is correct and dont lateDesign the following combinational logic circuit with a four-bit input and a three-bit output. The input represents two unsigned 2-bit numbers: A1 A0 and B1 B0. The output C2 C1.C0 is the result of the integer binary division A1 A0/B1 B0 rounded down to three bits. The 3-bit output has a 2-bit unsigned whole part C2 C1 and a fraction part CO. The weight of the fraction bit CO is 21. Note the quotient should be rounded down, i.e. the division 01/11 should give the outputs 00.0 (1/3 rounded down to 0) not 00.1 (1/3 rounded up to 0.5). A result of infinity should be represented as 11.1. A minimal logic implementation is not required. (Hint: start by producing a truth table of your design).