3 num_owls_zooA = int(input()) 4 num_owls_zoOB = int(input()) 5 num_owls_zooc = int(input()) 6 7 " Your solution goes here 8 9 print('Average owls per zoo:', int(avg_owls)) Run View your last submission v
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Sample output for inputs: 1 2 4Average owls per zoo: 2
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- def apply_gaussian_noise(X, sigma=0.1): """ adds noise from standard normal distribution with standard deviation sigma :param X: image tensor of shape [batch, 3, height, width] Returns X + noise. """ ### YOUR CODE HERE ### # noise tests theoretical_std = (X_train[:100].std() ** 2 + 0.5 ** 2) ** .5 our_std = apply_gaussian_noise(X_train[:100], sigma=0.5).std() assert abs(theoretical_std - our_std) < 0.01, \ "Standard deviation does not match it's required value. Make sure you use sigma as std." assert abs(apply_gaussian_noise(X_train[:100], sigma=0.5).mean() - X_train[:100].mean()) < 0.01, \ "Mean has changed. Please add zero-mean noise"function result = result = ''; 1 tokens_to_str_code(token_mat, time_unit) 3 for i =1:size(token_mat,1) 4 5 if(token_mat (i,1) if(token_mat(i,2) > 4*time_unit) result = strcat(result,"-"); elseif((token_mat(i,2) > time_unit) && (token_mat(i,2) 8*time_unit) result = strcat(result,"/"); elseif((token_mat(i,2) 11 == 0) 12 13 14 4*time_unit) && (token_mat(i,2) < 8*time_unit)) 15 result strcat(result," "); %3D 16 end 17 end 18 end 19 end 20 21 Check Test Expected Got tokens %3D [1 4; е 3; 1 3; е 1; 1 3; е 1; 1 1; ө 1; 1 1 ]; time_unit = .5; disp( tokens_to_str_code( tokens, time_unit )) tokens = [ 0 4; 1 1457; 0 463; 1 1457; 0 463; 1 497; 0 1423; 1 1457; ---/..--.. --.---/..--.. о 463; 1 1457; 0 463; 1 1457; ө 3343; 1 497; ө 463; 1 497; 0 463; 1 1457; 0 1423; 1 1457; 0 463; 1 497; 0 463; 1 497; e 379 ]; time_unit = 240; disp( tokens_to_str_code( tokens, time_unit ))bool validPassword=true; cin >> passPhrase;} if (passPhrase.length() <= 4) { validPassword = false; } else { int digitCount=0; for (int i = 0; i < passPhrase.length(); i++) { if (isdigit(passPhrase.at(i))) digitCount++; } if (digitCount > 4) { validPassword=false; } if (validPassword) { cout << "Valid" << endl; } else { cout << "Invalid" << endl; } return 0;} // it still comes up with these errors. Not sure what it is telling me. main.cpp:9:7: error: expected unqualified-id before ‘if’ 9 | if (passPhrase.length() <= 4) { | ^~ main.cpp:13:7: error: expected unqualified-id before ‘else’ 13 | else { | ^~~~
- Write the following methodthat tests whether the array has four consecutive numbers with the same value:public static boolean isConsecutiveFour(int[] values)Write a test program that prompts the user to enter a series of integers and displaysit if the series contains four consecutive numbers with the same value. Yourprogram should first prompt the user to enter the input size—i.e., the number ofvalues in the series. Here are sample runs: Enter the number of values: 8↵EnterEnter the values: 3 4 5 5 5 5 4 5↵EnterThe list has consecutive foursEnter the number of values: 9↵EnterEnter the values: 3 4 5 5 6 5 5 4 5↵EnterThe list has no consecutive foursimport mathEPSILON = 1.0e-14def square_root(number):approximation = 1previous = 0iterations = 0while ((absolute value of (approximation * approximation minus number)is greater than EPSILON) and previous != approximation):previous = approximationapproximation = 0.5 * (approximation + number / approximation)iterations += 1return (approximation, iterations)A spell checker in a word processing program makes suggestions when it finds a word not in the dictionary. To determine what words to suggest, it tries to find similar words. One measure of word similarity is the Levenshtein distance, which measures the number of substitutions, additions, or deletions that are required to change one word into another. For example, the words spit and spot are a distance of 1 apart; changing spit to spot requires one substitution (i for o). Likewise, spit is distance 1 from pit since the change requires one deletion (the s). The word spite is also distance 1 from spit since it requires one addition (the e). The word soot is distance 2 from spit since two substitutions would be required. a. Create a graph using words as vertices, and edges connecting words with a Levenshtein distance of 1. Use the misspelled word “moke” as the center, and try to find at least 10 connected dictionary words. How might a spell checker use this graph? b. Improve the method…
- Task 01: Assume P(x,y) is (x+y>4). Write a function/method that can validate the nested quantifier Vy P(x,y) for elements from two arrays X and Y. i. hint: The method returns l if statement is valid (the sum of all pairs of values from X and Y is greater than 4), and returns 0 otherwise. Valid case: For arrays X={2,3,4} and Y={3,4,5), the method returns 1(since xEX and býyEY, xi+y>4) Invalid case: For arrays X={2,3,4} and Y={1,4.5}, the method returns 0 (since 2EX and l EY but 2+1<4)*in java* Array testGrades contains NUM_VALS test scores. Write a for loop that sets sumExtra to the total extra credit received. Full credit is 100, so anything over 100 is extra credit. Ex: If testGrades = {101, 83, 107, 90}, then sumExtra = 8, because 1 + 0 + 7 + 0 is 8. import java.util.Scanner; public class SumOfExcess {public static void main (String [] args) {Scanner scnr = new Scanner(System.in);final int NUM_VALS = 4;int[] testGrades = new int[NUM_VALS];int i;int sumExtra = -9999; // Assign sumExtra with 0 before your for loop for (i = 0; i < testGrades.length; ++i) {testGrades[i] = scnr.nextInt();} /* Your solution goes here */ System.out.println("sumExtra: " + sumExtra);}}2. code locations Consider the following C code and the corresponding assembly code: void baz(int a, int * p) { pushq %rbp movq %rsp,%rbp subq $16,%rsp int c; C = a-*p; movl %ecx,16(%rbp) movq %rdx, 24(%rbp) movq 24(%rbp), %rax movl (%rax),%eax movl 16(%rbp),%edx subl %eax,%edx movl %edx,%eax movl %eax,-4(%rbp) cmpl $0, -4(%rbp) je L2 if (c) { int d = c*2; movl -4(%rbp),%eax addl %eax,%eax movl %eax,-8(%rbp) *p -= d; movl 24(%rbp),%rax movl (%rax),%eax subl -8(%rbp),%eax movl %eax,%edx movq 24(%rbp), %rax movl %edx, (%rax) jmp L4: (continued on next page)
- JAVA CODE PLEASE Functions With No Parameters and Return Values Quiz by CodeChum Admin Create a function named banner that prints “CodyChum” with a newline. In the main function, write a program that accepts an integer input which would serve as an inclusive stopping point of a loop iteration that starts at the value of 1. If the number that loops through the range is divisible by either 2 or 3, then call the banner function, otherwise just print the number. Input 1. One line containing an integer Output First line is the integer user input. Succeeding multiple lines containing an integer or “CodyChum” 10 1 CodyChum CodyChum CodyChum 5 CodyChum 7 CodyChum CodyChum CodyChumDeclare an array that represents 100 students. Assign the examscores between 0 and 100 randomly into this array. Write amethod and display that assigns letter grade equivalents of theexam scores to a second array. Display the number ofunsuccessful students.The grade scala is as follows:100 – 90 : A89 – 80 : B79 – 70 : C69 – 60 : D59 – 0 : F (unsuccessful) (Write in java)void traceMe(double x, double y) { double z; z = (pow(x, y)); cout « fixed « showpoint <« setprecision(2)<« x « ", " « y « ", " « z « endl; int main() double one=2, two=6; traceMe(two, one); 2.00 , 6,00 , 36.00 6.00 , 2.00 , 36.00 6.00 , 2,00 , 64.00 O 6.00, 2.00, 4,00