3. A 0.3246 g sample that might contain NaOH, Na₂CO,, NaHCO, or a permissible mixture of the bases is titrated with 0.0828 M HC by the double-indicator method. It is found that 30.38 ml of the acid are required to reach the phenolphthalein end point. Methyl orange is then added to the solution and the titration continued using an additional of 7.83 ml of the acid. Calculate the % of each in the sample?

Appl Of Ms Excel In Analytical Chemistry
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Chapter7: Neutralization Titrations And Graphical Representations
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3. A 0.3246 g sample that might contain NaOH, Na₂CO,, NaHCO, or a permissible
mixture of the bases is titrated with 0.0828 M HCl by the double-indicator
method. It is found that 30.38 ml of the acid are required to reach the
phenolphthalein end point. Methyl orange is then added to the solution and the
titration continued using an additional of 7.83 ml of the acid. Calculate the % of
each in the sample?
4. The protein in a 1.2846-g sample of an oat cereal is determined by the Kjeldahl
procedure for organic nitrogen. The sample is digested with H₂SO4, the resulting
solution made basic with NaOH, and the NH, distilled into 50.00 mL of 0.09552 M
HCI. The excess HCI is then back titrated using 37.84 mL of 0.05992 M NaOH.
Given that the protein in grains averages 17.54% w/w N, report the % w/w
protein in the sample of cereal.
Transcribed Image Text:3. A 0.3246 g sample that might contain NaOH, Na₂CO,, NaHCO, or a permissible mixture of the bases is titrated with 0.0828 M HCl by the double-indicator method. It is found that 30.38 ml of the acid are required to reach the phenolphthalein end point. Methyl orange is then added to the solution and the titration continued using an additional of 7.83 ml of the acid. Calculate the % of each in the sample? 4. The protein in a 1.2846-g sample of an oat cereal is determined by the Kjeldahl procedure for organic nitrogen. The sample is digested with H₂SO4, the resulting solution made basic with NaOH, and the NH, distilled into 50.00 mL of 0.09552 M HCI. The excess HCI is then back titrated using 37.84 mL of 0.05992 M NaOH. Given that the protein in grains averages 17.54% w/w N, report the % w/w protein in the sample of cereal.
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