Vector Method: T₁₂ 80° 60° Fg T₁ 40° <3 marks sin 80° sin 60° F g T₁ sin 60° T F sin 80° g -0.879-35 kg-9.8 m/s² -3.0 x 10² N 1 marks F mg (35 kg)(9.8 N/kg) - 343 N - 1 mark = sin 80° sin 40° F g Τ2 T₁-2.2 × 10² N 1 marks 001phk -6- February 24, 2000 3. A 35 kg traffic light is suspended from two cables as shown in the diagram. Cable 1 100° 140° 120° Cable 2 What is the tension in each of these cables? Component Method: 001phk T₁ T₂ 50° 30° - 2 marks cos 30° ΣΕ = 0 T₁ cos 50°-7, cos 30° T-T ΣΕ, = 0 cos 30° cos 50° T₁ sin 50° +T2 sin 30° = 35(9.8) cos 50° sin 50° +T₂ sin 30° = 343 343 T:- 1.03+0.5 T₂ = 224 N T₁ = 224 cos 30° cos 50° = 302 N (7 marks) -5- February 24, 2000

Vector Method: T₁₂ 80° 60° Fg T₁ 40° <3 marks sin 80° sin 60° F g T₁ sin 60° T F sin 80° g -0.879-35 kg-9.8 m/s² -3.0 x 10² N 1 marks F mg (35 kg)(9.8 N/kg) - 343 N - 1 mark = sin 80° sin 40° F g Τ2 T₁-2.2 × 10² N 1 marks 001phk -6- February 24, 2000 3. A 35 kg traffic light is suspended from two cables as shown in the diagram. Cable 1 100° 140° 120° Cable 2 What is the tension in each of these cables? Component Method: 001phk T₁ T₂ 50° 30° - 2 marks cos 30° ΣΕ = 0 T₁ cos 50°-7, cos 30° T-T ΣΕ, = 0 cos 30° cos 50° T₁ sin 50° +T2 sin 30° = 35(9.8) cos 50° sin 50° +T₂ sin 30° = 343 343 T:- 1.03+0.5 T₂ = 224 N T₁ = 224 cos 30° cos 50° = 302 N (7 marks) -5- February 24, 2000

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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