3. Habang may Tatsulok. Consider the point charge dis-tribution in the figure. What is the magnitude of the netelectric force on the charge Q = +q that lies at the topof the triangle?Q= +qakq?А.a²С.a?V3kq?В.a?V2kq²D.a?2kq?+q+qa4. UEFA. An electron is released from rest in a uniform electric field. The electron accelerateshorizontally to the right and travels 2.50 m in the first 5.00 µus after it is released. What are themagnitude and direction of the electric field? Disregard the effects of gravity.A. 0.569 N/C to the leftC. 1.14 N/C to the leftD. 1.14 N/C to the rightB. 0.569 N/C to the right

Given that:- Charge on each vertices of equilateral triangle=+q

3. Habang may Tatsulok. Consider the point charge dis- tribution in the figure. What is the magnitude of the net electric force on the charge Q = +q that lies at the top of the triangle? Q = +q kq? А. V3kq? a² C. a² V2kq? 2kq² В. a² D. a? +q +q a

3. Habang may Tatsulok. Consider the point charge dis- tribution in the figure. What is the magnitude of the net electric force on the charge Q = +q that lies at the top of the triangle? Q = +q kq? А. V3kq? a² C. a² V2kq? 2kq² В. a² D. a? +q +q a

University Physics Volume 2

18th Edition

ISBN:9781938168161

Author:OpenStax

Publisher:OpenStax

Chapter5: Electric Charges And Fields

Section: Chapter Questions

Problem 67P: Consider an electron that is 1010 m from an alpha particle (q=3.21019C) . (a) What is the electric...

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Question

3. Habang may Tatsulok. Consider the point charge dis-
tribution in the figure. What is the magnitude of the net
electric force on the charge Q = +q that lies at the top
of the triangle?
Q= +q
a
kq?
А.
a²
С.
a?
V3kq?
В.
a?
V2kq²
D.
a?
2kq?
+q
+q
a
4. UEFA. An electron is released from rest in a uniform electric field. The electron accelerates
horizontally to the right and travels 2.50 m in the first 5.00 µus after it is released. What are the
magnitude and direction of the electric field? Disregard the effects of gravity.
A. 0.569 N/C to the left
C. 1.14 N/C to the left
D. 1.14 N/C to the right
B. 0.569 N/C to the right

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