3. I am crossing two individuals. One is homozygous recessive for color, height, and shape. The other individual is homozygous dominant for color, height, and shape displaying a yellow, tall, and round phenotype. The offspring of this pairing are either: a. Yellow, tall, and round b. Tall and round c. Yellow
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- In cats, the genotype AA produces tabby fur color; Aa is also a tabby, and aa is black. Another gene at a different locus is epistatic to the gene for fur color. When present in its dominant W form (WW or Ww), this gene blocks the formation of fur color and all the offspring are white; ww individuals develop normal fur color. What fur colors, and in what proportions, would you expect from the cross AaWw Aa Ww?2. The following is a pedigree of a family in which a rare form of X-linked colorblindness is found (filled-in symbols). II 2 II 3 4 a. Label the genotypes of as many family members as the available information permits. Remember that this gene is located on the X-chromosome when writing out genotypes. b. Is the colorblindness trait recessive or dominant? Explain how you know.1. In pea plants, yellow color (Y) is dominant over green color (y). A yellow-colored pea plant is crossed with a green-colored pea plant. Half of their offspring is yellow-colored while the other half is green-colored.What is the genotype of the yellow-colored parent? YY O Yy yy The genotype cannot be determined. 2. A scientist discovered an unknown organism in a tropical rainforest. The organism has been identified to possess the following characteristics: (1) multicellular at some point of its life cycle; (2) feeds on decaying organic matter; and (3) has a cell wall made of chitin.Which Kingdom does the unknown organism likely belong to? Kingdom Animalia Kingdom Plantae Kingdom Fungi Kingdom Protista 3. Which statement about ferns is TRUE? Ferns are unicellular organisms. Ferns are nonvascular plants. O Ferns have spores as reproductive structures. Ferns are capable of secondary growth.
- 10. In the video example, the sex-linked disorder was a recessive trait. However, sex-linked disorders can be dominant! (Conduct a search to see some of the sex-linked dominant disorders that exist). Sex- linked dominant disorders will show even if there is only one dominant allele present. Using the allele D to stand for a dominant sex-linked trait, show a cross with a woman who does not have a dominant sex-linked disorder (X*Xª) with a man that does. Will the disorder in this particular cross be more common in daughters or sons?8. This family pedigree follows a family afflicted by a trait determined by the R gene IdA 2 9 10 11 12 13 14 15 16 17 18 19 e. What is the genotype of individual 1: f. What is the genotype of individual 6: g. What is the genotype of individual 2: h. What is the genotype of individual 13: i. Is this trait autosomal dominant, recessive, or X-linked recessive? Why? |1.In humans, one type of red-green color blindness is a sex-linked recessive. Normal color vision is dominant to color blindness. a. Two parents with normal vision produce a colorblind son. What are the genotypes of the parents? heterozygous for x-1inked trait mother IS carrier i father XY ANX is normal b. What are the chances of their next child being a colorblind female? c. What are the chances of their next child being a son with normal vision?
- III. Dihybrid crosses Two loci with two autosomal recessive traits Gene symbols a apterous wing size A normal wing size s sepia eye color S red eye color Be careful, S and s look alike when hand written The parents were apterous, red eyed color female and normal wing size, sepia eyed coloredmale (figure out the genotypes) Diagram of P1 cross: You are crossing AaSs with AaSs. Diagram of F1 cross: Give expected F2 phenotypic ratio: Give expected F2 genotypic ratio: IV. Other dihybrid cross Gene symbols v vestigial wing size V normal wing size s sepia eye color S red eye color The parents were vestigial, red eyed color female and normal wing size, sepia eyed color male…1. How many different types of gametes can be produced by an individual with the genotype Yy Ww Pp ee Bb? 2. If an individual with the genotype Yy Ww Pp ee Bb is crossed with another individual with the same genotype, what proportion of offspring will be homozygous recessive at all genes? 3. If an individual with genotype Yy Ww Pp ee Bb is crossed with an individual with the same genotype, what proportion of offspring will have the dominant phenotype for the four heterozygous loci?1. You are given a female F1 of unknown genotype. You cross the female fly to a homozygous male that has forked bristles and malformed eyes. The offspring of the cross is shown below: (Define symbols for your traits) Phenotype Forked bristles, normal eyes 752 Number Genotype Forked bristles, malformed 56 eyes Malformed eyes, normal bristles Normal eyes, normal bristles 820 64 a. What are the genotypes of the offspring? b. Based on the progeny, what were the genotypes of the F1 parents? What is the distance between for and mal?
- 7. In pea plants, the dominant allele for flower color is yellow (Y), and the recessive allele is white (y). If a homozygous dominant (YY) yellow-flowered plant is crossed with a heterozygous (Yy) yellow flowered plant what will be the possible genotypes and phenotypes of the offspring? Possible genotypes: Possible phenotypes:1. In fruit flies, the phenotype for eye color is determined by a certain locus. E indicates the dominant allele and eindicates the recessive allele. The cross between a male wild-type fruit fly and a female white-eyed fruit flyproduced the following offspring.Wild-typeMaleWild-typeFemaleWhite-eyedMaleWhite-eyedFemaleBrown-eyedFemaleF1 0 45 55 0 1The wild-type and white-eyed individuals from the F1 generation were then crossed to produce the followingoffspring.F2 23 31 22 24 0(a) Determine the genotypes of the original parents (P generation) and explain your reasoning. You may usePunnett squares to enhance your description, but the results from the Punnett squares must be discussed inyour answer.(b) Use a Chi-squared test on the F2 generation data to analyze your prediction of the parental genotypes. Showall your work and explain the importance of your final answer.(c) The brown-eyed female in the F1 generation resulted from a mutational change. Explain what a mutation is,and discuss…9. Make a pedigree for each of the following situations. For each individual, write the individual's genotype (when possible) next to the individual's symbol (e.g. O xty, I Gg): a. Two parents do not have cystic fibrosis and they have a daughter with cystic fibrosis and a son who does not have cystic fibrosis. The daughter grows up and she mates with a male who does not have cystic fibrosis. Their only child is a boy and he has cystic fibrosis. b. A man with hemophilia mates with a female without hemophilia. They have one son and one daughter. The daughter has hemophilia and the son does not have hemophilia. The son grows up, and he marries and mates with a female. Their only child is a boy, and he has hemophilia.