3. Three bars each made from different materials are placed between walls when the temperature is14°C. Determine the support reaction when the temperature becomes 19°C. The material properties aregiven in the figure.Answer: R = 3502.30 NSteelBrassCopperEbr 100 GPaEcu = 120 GPaEst=200 GPaast = 12(10-6)/°Cabr = 21(106)/Cacu = 17(10-6)/°CAcu = 515 mm²|Ast = 200 mm² Abr= 450 mm²-300 mm-200 mm-100 mm4. The rigid slab is supported by two identical copper rods as shown. The copper rod has an area of 500mm² with a = 16.8 μm/ (m°C) and E = 120 GPa. There is a gap of 0.18 mm between the slab and thealuminum rod. The aluminum rod has an area of 400 mm² with a = 23.1 μm/ ( mºC) and E = 70 GPa.Compute the stress developed in each rod when the temperature is raised to 85°C. Assume that theweight of the slab is negligible.Answer: OAI = 16.80 MPa85→TAΔCopperAluminumCopper750 mm-

Answered: Image /qna-images/answer/e3a3166a-d9e7-41cd-ada6-ff319d18e965.jpg

3. Three bars each made from different materials are placed between walls when the temperature is 14°C. Determine the support reaction when the temperature becomes 19°C. The material properties are given in the figure. Answer: R = 3502.30 N Steel Brass Copper Ecu 120 GPa Est = 200 GPa ast=12(106)/°C Ebr = 100 GPa abr 21(106)/C = au = 17(10-6)/°C Acu = 515 mm² |Ast = 200 mm² Abr 450 mm² -300 mm- 100 mm -200 mm-

3. Three bars each made from different materials are placed between walls when the temperature is 14°C. Determine the support reaction when the temperature becomes 19°C. The material properties are given in the figure. Answer: R = 3502.30 N Steel Brass Copper Ecu 120 GPa Est = 200 GPa ast=12(106)/°C Ebr = 100 GPa abr 21(106)/C = au = 17(10-6)/°C Acu = 515 mm² |Ast = 200 mm² Abr 450 mm² -300 mm- 100 mm -200 mm-

Mechanics of Materials (MindTap Course List)

9th Edition

ISBN:9781337093347

Author:Barry J. Goodno, James M. Gere

Publisher:Barry J. Goodno, James M. Gere

Chapter1: Tension, Compression, And Shear

Section: Chapter Questions

Problem 1.6.7P: A wine of length L = 4 ft and diameter d = 0.125 in. is stretched by tensile forces P = 600 lb. The...

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