3. Use a stack to evaluate the following postfix expression. 3 5 7 + 2 1 - * 1 + +
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- D. If the values of A, B , C and D are 2, 3, 4 and 5 respectively, manually calculate the value of the following postfix expressions using stack. a. AB*C-D+ b. ABC +*D- ||Create a C code that will allow the user to input a word and check whether it is a palindrome or not. Use a stack to reverse the order of a string and identify whether it is a palindrome or not. It should not be case-sensitive. Example 1: Input string: Racecar Reversed string: RACECAR (Note, this can also be all lowercase) Palindrome: Yes exampl 2: Input string:caRrot Reversed string: TORRAC(Note, this can also be all lowercase) Palindrome: No Note: maximum string length is 201. Read input 5 integer values from the user and print them in the reverse order of their input using a stack data structure. Programming languages allowed: C++/JAVA/Python
- 7. The following function converts a postfix expression to an infix expression assuming the expression can only contain unsigned integer numbers and +' and -' operators. 1. public static String convert (String postfix) { 2. String operand1, operand2, infix; 3. Stack s = new AStack; 4. int i = 0; 5. while (i < postfix.length) { char nextc = postfix.charAt (i); if ((nextc 6. 7. '+')|| (nextc == '-') { == operand2 = s.pop (); operandl = s.pop () ; infix = '(' + operandl + nextc + operand2 + ')'; s.push (infix); i++; 8. 9. 10. 11. } 12. else if (Character.isDigit (nextc)){ int start = i; while (Character.isDigit (postfix.charAt (i)) i++; infix = postfix.substring (start, i); s.push (infix); 13. 14. 15. 16. 17. } else i++; 18. 19. } 20 return s.pop () ; 21. } (a) Rewrite only the lines of code that need to be changed so that the above function converts a postfix expression to a prefix expression. (b) Describe in words what changes are needed on the above given convert () function so that it…T/F An error is thrown if the character '\n' is pushed in to the character stack.C PROGRAM Write a program that asks the user values for the coefficient A,B, and C in the quadratic equation Ax^2 + Bx + C= 0, and then prints the solution/s of the equation (if there is/are any) For this problem, you need to include the following header file: math.h So that you can use the C library function sqrt() The function sqrt() computes the square root of a value (in double) Use #include <stdio.h>
- a) Select whether the statement is True or False. i. A stack is a data structure in which the items can be added and deleted from both ends of the structure. (True / False) ii. The basic operations on a stack are as follows: Push an item onto the stack, pop an item from the stack, retrieve the top element of the stack, initialize the stack, check whether the stack is empty, and check whether the stack is full. (True / False) ii. The middle elements of a stack could be accessed directly. (True / False) iv. Postfix notation does not require the use of parentheses to enforce operator precedence, and the operators are written after the operands. T(True / False) b) Convert the following infix expressions to postfix notations. i. (A + B) * (C + D) - E ii. A (B + C) * D + E / F iii. ( (A + B) / (C - D) + E) * F - G iv. A + B * (C + D) E / F * G + H2- The factorial n! of a positive integer n is defined as n! = 1*2*3 . .. * (n-1) * n Where 0! = 1 Write a function to calculate the factorial of a number. Argument: A number n of type unsigned int. Returns: The factorial n! of type long double. Write two versions of the function, where the factorial is • calculated using a loop calculated recursively Test both functions by outputting the factorials of the numbers 0 to 20.#include<stdio.h>#include<stdlib.h>#include<string.h>/* function that converts the change into count of 50,20,10,5 and stores the count in changeArray*/int coinChange(int changeArray[10][4],int index,int change){int count50=0,count20=0,count10=0,count5=0;while(change > 0){if(change > 0 && change <=95 && change% 5 == 0){if(change >= 50){change -= 50;count50++;}else if(change >= 20){change -= 20;count20++;}else if(change>=10){change -= 10;count10++;}else if(change>=5){change -= 5;count5++;}}}changeArray[index][0]=count50;changeArray[index][1]=count20;changeArray[index][2]=count10;changeArray[index][3]=count5;return change;}/* function that reads 'coins.txt' and stores names in names array, coin values in coins array, compute change and stores change count in change array */int readFromFile(char names[10][100],int coins[],int change[10][4]){int index=-1,i=0;FILE *fp;fp=fopen("coins.txt","r");if(fp==NULL){printf("File doesnot…
- Use the following code to perform the following tasks: Show all variables that are visible at POSITION #1 only. Provide their nesting level and offset, using the activation record layout discussed in class.S2how the contents of the call stack at the time when control reaches POSITION #1. Use the layout defined in chapter 10 and used in class for statically scoped languages that allow nested functions. Show values and links. function main() {int w = 1, x = 2; function a(bool flag) {int x = 3; function b() { c(4); } function c(int x) {// POSITION #1 } b(); } a(true); } Provide a leftmost derivation for the string aaabb using the following grammar:<S> → <A><B> <A> → a<A> | a <B> → b<B> | b Identify the shortest possible legal program: <program> → program <ident> ( <ident> { , <ident> } ) <block> <ident> → A | B<block> → begin <stmts> end <stmts> → <ident> = <ident> |…def main(): x = 1 y = 2 swap(x, y) print(x, y) def swap(s1, s2): temp = s1 s1 = s2 s2= temp main() Modify the code so that it actually swaps the values of x and y, without using the temp variable in the swap function.Code write () 9.