3.18. A manufacturer of television sets is interested in the effect on tube conductivity of four different types of coating for color picture tubes. A completely randomized experiment is conducted and the following conductivity data are obtained: Coating Type 1 234 2 4 143 152 134 129 Conductivity 150 137 132 132 141 149 136 127 146 143 127 129 (a) Is there a difference in conductivity due to coating
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- Three adhesives are being analysed for their impact on the bonding strength of paper in a pulp and paper mill. The adhesives are each randomly applied to four batches. The data is shown in Table 2. Here, the three treatments are the adhesives (p=3) and the number of replications for each treatment is 4 (r=4). Is there a difference among the adhesives in terms of the mean bonding strength? Test at the 5% significance level. Given F0.05,2,9 = 4.26 Adhesive Bonding strength (kg) type Adhesive 1 10.2 11.8 Adhesive 2 12.8 14.7 Adhesive 3 7.2 9.8 Table 2 Bonding strength data 9.6 13.3 8.7 12.4 15.4 9.2The article “Ozone for Removal of Acute Toxicity from Logyard Run-off” (M. Zenaitis and S. Duff, Ozone Science and Engineering, 2002: 83–90) presents chemical analyses of runoff water from sawmills in British Columbia. Included were measurements of pH for six water specimens: 5.9, 5.0, 6.5, 5.6, 5.9, 6.5. Assume that these are a random sample of water specimens from a normal population. a) Find a 98% prediction interval for a pH of a single specimen. b) Find a tolerance interval for the pH that includes 95% of the specimens with 95% confidence.The human resources director of a large company recently asked her staff to conduct a study of the airline miles traveled by executives of the company during the most recent calendar year. The analyst assigned to the project randomly sampled 25 male executives and 25 female executives. Of particular interest to the HR director is whether males have greater variability in miles flown than females. The statistics available below were computed from the samples. Based on these data, what should the HR director conclude if an alpha level equal to 0.01 is used? LOADING... Click the icon to view the statistics about the number of miles flown. Males Females Mean Miles 73,262 66,888 St. Deviation Miles 2,568 1,539 Sample Size 25 25 Let sample 1 be males and sample 2 be females. What are the null and alternative hypotheses? A. H0: σ21=σ22 HA: σ21≠σ22 B. H0: σ21≤σ22 HA: σ21>σ22 C. H0: σ21≥σ22 HA:…
- 3.20 A manufacturer of television sets is interested in the effect on tube con- ductivity of four different types of coating for color picture tubes. A completely randomized experiment is conducted and the following conductivity data are obtained: Coating Type Conductivity 1 143 141 150 146 2 152 149 137 143 3 134 136 132 127 4 129 127 132 129 (a) Is there a difference in conductivity due to coating type? Use a = 0.05. (b) Estimate the overall mean and the treatment effects. (c) Compute a 95 percent confidence interval estimate of the mean of coating type 4. Compute a 99 percent confidence interval estimate of the mean difference between coating types 1 and 4 . (d) Test all pairs of means using the Fisher LSD method with a = 0.05.The article "Solid-Phase Chemical Fractionation of Selected Trace Metals in Some Northern Kentucky Soils" (A. Karathanasis and J. Pils, Soil and Sediment Contamination, 2005:293-308) presents pH measurements of soil specimens taken from three" different types of soils. The results in the following table are consistent with" means and standard deviations reported in the article. Soil Type pH Measurements Alluvium 6.53, 6.03, 6.75, 6.82, 6.24 Glacial 6.07, 6.07, 5.36, 5.57, 5.48, 5.27, 5.80, 5.03, 6.65 Till Residuum 6.03, 6.16, 6.63, 6.13, 6.05, 5.68, 6.25, 5.43, 6.46, 6.91, 5.75, 6.53 Construct an ANOVA table. You may give a range for the P-value. Can you conclude that there are differences among the mean pH levels? a. b.An experiment was conducted to determine the effect of machining factors on ceramicstrength. Two levels of table speed (slow and fast), two directions (longitudinal and transverse) and two levelsof wheel grit (I and II) were identified by the researcher. The experiment was replicated three times and thestrength of each randomly selected ceramic was obtained. The ANOVA table of the results of the analysis areas follows. 1. Refer to the ANOVA table at a=0.01, what is the conclusion for testing significance in 3-way interaction Reject/Fail to Reject Ho 2. If sequential test of hypothesis is performed the following are (True or False)? a. All 2-way interaction effects are going to be tested b. All main effects are going to be tested 3. What combination of effects will result to a significant result at a=0.01 if should all test are going to be performed among the main effects and two way interactions? (choose 1pair/combination: direction, wheel grit, speed)
- Rhino viruses typically cause common colds. In a test of the effoctivoness of echinecea, 32 of the 39 subjects treated with echinacea developed ithinavirus infections In a placebo group, 90 of the 107 subjects developed thinovirus infections Use a 0.05 significance level to test the clam that echinacea has an effect on thinovinus infections Complete parts (a) through (c) below COO a. Test the claim using a hypothesis test Consider the first sample to be the sample of subjects treated with echinacea and the second samplo to be the sample of subjects troated with a placebo What are the null and alternative hypotheses for the hypothesis test? OA Ho P P2 H P P2 OB. Ho P P2 H P, P2 H, P Pa VE Ho Pr"P2 Hy P,P OF M PPa H, P P |OD. Ho P1 P2 H, P P2 Identify the test statistic (Round to two decimal places as noeded)An article described an experiment in which observations on various characteristics were made using minichambers of three different types: (1) cooler (PVC frames covered with shade cloth), (2) control (PVC frames only), and (3) warmer (PVC frames covered with plastic). One of the article's authors kindly supplied the accompanying data on the difference between air and soil temperatures (°C). Cooler 1.59 1.43 1.88 1.26 1.91 1.86 1.90 1.57 1.79 1.72 2.41 2.34 0.94 1.34 1.76 Control 1.92 2.00 2.19 1.12 1.78 1.84 2.45 2.03 1.52 0.49 1.90 Warmer 2.57 2.60 1.93 1.58 2.30 0.84 2.65 0.15 2.74 2.53 2.13 2.86 2.31 1.91 (a) Compare measures of center for the three different samples. Cooler X = 1.76 Control X = 1.90 Warmer X = 2.305 (b) Calculate the standard deviations for the three different samples. (Round your answers to three decimal places.) Cooler S = 0.395 Control S = 0.522 Warmer S = 0.772 X x Interpret and compare the standard deviations for the three different samples.A study of bone density on 5 random women at a hospital produced the following results. Age 49 57 61 65 69 Bone Density 355 345 340 325 320 Step 1 of 3: Calculate the correlation coefficient, r. Round your answer to six decimal places. Step 2 of 3: Determine if r is statistically significant at the 0.01 level. Step 3 of 3: Calculate the coefficient of determination, r2. Round your answer to three decimal places.
- Blood cocaine concentration (mg/L) was determinedboth for a sample of individuals who had died fromcocaine-induced excited delirium (ED) and for a sampleof those who had died from a cocaine overdose withoutexcited delirium; survival time for people in bothgroups was at most 6 hours. The accompanying datawas read from a comparative boxplot in the article“Fatal Excited Delirium Following Cocaine Use” (J.of Forensic Sciences, 1997: 25–31). ED 0 0 0 0 .1 .1 .1 .1 .2 .2 .3 .3.3 .4 .5 .7 .8 1.0 1.5 2.7 2.83.5 4.0 8.9 9.2 11.7 21.0Non-ED 0 0 0 0 0 .1 .1 .1 .1 .2 .2 .2.3 .3 .3 .4 .5 .5 .6 .8 .9 1.01.2 1.4 1.5 1.7 2.0 3.2 3.5 4.14.3 4.8 5.0 5.6 5.9 6.0 6.4 7.98.3 8.7 9.1 9.6 9.9 11.0 11.512.2 12.7 14.0 16.6 17.8 a. Determine the medians, fourths, and fourth spreadsfor the two samples.b. Are there any outliers in either sample? Any extremeoutliers?c. Construct a comparative boxplot, and use it as abasis for comparing and contrasting the ED andnon-ED samples.Fiber Density. In the article “Comparison of Fiber Counting by TV Screen and Eyepieces of Phase Contrast Microscopy” (American Industrial Hygiene Association Journal, Vol. 63, pp. 756–761), I. Moa et al. reported on determining fiber density by two different methods. The fiber density of 10 samples with varying fiber density was obtained by using both an eyepiece method and a TV-screen method. A hypothesis test is to be performed to decide whether, on average, the eyepiece method gives a greater fiber density reading than the TV-screen method. a. identify the variable. b. identify the two populations. c. identify the pairs. d. identify the paired-difference variable. e. determine the null and alternative hypotheses. f. classify the hypothesis test as two tailed, left tailed, or right tailed.Q No.5) Four different paints are advertised as having the same drying time. To check the manufacturer's claim, five samples of each paint were tested. The time in minutes until the paint was dry enough for a second coat to be applied was recorded. The following data were obtained. Paint 1 Paint 2 Paint 3 Paint 4 128 144 133 150 137 133 143 142 135 142 137 135 124 146 136 140 141 130 131 153 At the 0.05 level of significance, test to see whether the mean drying time is the same for each type of paint.