30° 53.65° V=220/30° I=6.96 Z-53.65° ►X For the following phasor diagram find: 1- The total impedance value (ZT) 2- The values of the circuit component 3- Draw the circuit 4- The total phase difference angle 5- The value of capacitance to be added to the circuit to make its effect resistive
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- Shown in the figure below is an "RC" circuit drive by an AC power source. The AC power source has an RMS voltage of Vps (RMS) = 11.58 Volts and is running at a frequency of f = 1.326e+04 Hz. resistor has a resistance of R = 3750 2 and the capacitor has an capacitance of C = 3.17e-09 Farads. Vps R ww Write the FORMULA for the total impedance of the circuit Ztot = Write the FORMULA for the phase of the total impedance of the circuit tot = Determine the numerical value of Ztot = Determine the numerical value of Pztot= Determine the current through the circuit: • I(PEAK) = • I(RMS) = Determine the voltage across the resistor: Amps Amps S2 C degreesShown in the figure below is an "RL" circuit drive by an AC power source. The AC power source has an RMS voltage of Vps (RMS) = 9.84 Volts and is running at a frequency of f = 8.585e+04 Hz. The resistor has a resistance of R = 2170 and the inductor has an inductance of L = 3.54e-03 Henries. Vps R ww Write the FORMULA for the total impedance of the circuit Ztot = Determine the numerical value of Ztot = 2890.5 Determine the numerical value of $z= = 41 Determine the current through the circuit: • I(PEAK) = 4.81E-3 • I(RMS) = 3.404E-3 Determine the voltage across the resistor: • VR(PEAK) = 7.387 • VR(RMS) = 5.22 ✔✔ Amps ✔Amps Write the FORMULA for the phase of the total impedance of the circuit z... = | tan-1 2701 R x Volts X Volts Determine the voltage across the inductor: • VL(PEAK) = 9.184 • VL(RMS) = 6.49 ✔ Volts Volts L R²+ WL- ✔ degrees 2 If a second circuit were connected in parallel with the inductor, this circuit would be considered as: O a low-pass filter O a capacitive switcher…Two lossy capacitors with Equal capacitance values and power factors of 0.01 and 0.02 are in parallel, and the combination is supplied from a sinusoidal voltage source. The power factor of the combination is ?
- C. Draw a general sine wave V vs t and I vs t plot for a purely resistive and a purely inductive circuit and show leading lagging parameters and clearly mark the phase difference.QUESTION 5 A resistor, a capacitor, an inductor, and a mystery component are connected in parallel. The resistor has a resistance of 300N, the capacitor has a reactance of 2500, and the inductor has a reactance of 6000. The total impedance of the circuit is 59.52-j119.640. What is the mystery component? O there is no mystery component O resistor O inductor O capacitor2-A resultant current is made of two components: a 10 A D.C. component and a sinusoidal component of maximum value 14.14. The average value of the resultant current is amperes (a) 0 (b) 24.14 (c) 10 (d) 4.14 and r.m.s. value is - amperes (e) 10 (f) 14.14 (g) 24.14 (h) 100
- ESSAY: Describe what happens to the power in this RLC series circuit as the capacitance decreases. Explain in general terms why the observed change should occur. Understand the effects of basic electrical components on the average power of the system and the concept of power factor. Differentiate between average power and real power.What is the value of capacitance if the capacitive reactance is 50 Q .Assume frequency of supply as 50 Hz ? a. 53.3x10-5 F O b. 5.3x10-5 F c. 6.36x10-5 E d. 63.3x10-5 FDraw phasor diagrams for the following:
- QUESTION 4 A resistor, a capacitor, and an inductor are connected in series with a function generator. The resistor has a resistance of 1.5k2, the inductor has a reactance of 1.2kQ, and the capacitor has a reactance of 2002. The circuit has a total current of 172mA RMS. Find the total voltage. O 310V233.7 O 74.5VL-14° 188V273.2 O 44.4VL-25.3°what is the reactive power absorbed by the load ZL in VAR? Assume source is in rmsProb. I and Vc For the following RMS phasor circuit, a coworker has determined values for 50 Ohms 50 Ohms i,- 225 2253.13° = 190.92 + 254.56 VRMS R1 + R2 Vc = 237.17/26.565° = 212.13+ 106.07 VRMS 100 2 -3Z98.13° =-0.4243 + J2.970 ARMS C -j60 Ohms For this problem provide at least 3 digits of precision for the answers. The results for the following calculations are to be answered in - a) Find the current I b) Determine the real (P) and reactive(Q) power DELIVERED by the source c) Determine the real (P) and reactive (Q) power ABSORBED by each impedance ( resistors R1 and R2, inductor and capacitor). The values for P and Q can be positive or negative. Remember S =P+jQ, so do not include the j with your answer for Q. Each of these answers will require two parts. For the phasor a magnitude and angle will be needed. For the powers, The real power P and the reactive power Q are required.