Solve problem 4-3.18, if the loads Q are zero and each P = 2000 lb Also solve, P-4-3.19, if each load P = 1500 lb and each load Q = 2500 lb 4-4 Method of Sections1254-3.17. Find the force in members AB, AC, BC, BID, CD, and CE forthe truss shown in Fig. P-4-3.17. Assume that the loads P are zero andthat each load () = 4000 1lb.%3DBD = 5660 lb C; CE = 6940 lb T%3D%3D4-3.18. Repeat Prob. 4-3.17 if the loads Q are zero and each loadP = 2000 lb.%3D4-3.19. Repeat Prob. 4-3.17 if each load P = 1500 lb and each loadQ = 2500 lb.%3DBD = 4440 lb C; CE = 5065 lb T%3D4-4 METHOD OF SECTIONSWe have seen that the method of joints consists of analyzing trussesthe principles of equilibrium to the concurrent forceof Figure P-4-3.1745°09.0909.090975°75°09H.B.09D.P.

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Answered: 4-3.18. Repeat Prob. 4-3.17 if the…

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4-3.18. Repeat Prob. 4-3.17 if the loads Q are zero and each load P = 2000 lb.

Mechanics of Materials (MindTap Course List)

9th Edition

ISBN:9781337093347

Author:Barry J. Goodno, James M. Gere

Publisher:Barry J. Goodno, James M. Gere

Chapter10: Statically Indeterminate Beams

Section: Chapter Questions

Problem 10.4.8P: The continuous frame ABC has a pin support at /l, roller supports at B and C, and a rigid corner...

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Concept explainers

Slope and Deflection

The slope in a deflected beam is described as an angle in radians made by the tangent of the section with the original axis of the beam. The deflection at any point on the axis of the beam is defined as the lateral displacement of the point before and after loading.

Question

Solve problem 4-3.18, if the loads Q are zero and each P = 2000 lb

Also solve, P-4-3.19, if each load P = 1500 lb and each load Q = 2500 lb

4-4 Method of Sections
125
4-3.17. Find the force in members AB, AC, BC, BID, CD, and CE for
the truss shown in Fig. P-4-3.17. Assume that the loads P are zero and
that each load () = 4000 1lb.
%3D
BD = 5660 lb C; CE = 6940 lb T
%3D
%3D
4-3.18. Repeat Prob. 4-3.17 if the loads Q are zero and each load
P = 2000 lb.
%3D
4-3.19. Repeat Prob. 4-3.17 if each load P = 1500 lb and each load
Q = 2500 lb.
%3D
BD = 4440 lb C; CE = 5065 lb T
%3D
4-4 METHOD OF SECTIONS
We have seen that the method of joints consists of analyzing trusses
the principles of equilibrium to the concurrent force
of

Figure P-4-3.17
45°
09
.09
09
.09
09
75°
75°
09
H.
B.
09
D.
P.

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