4. In January a facility has a peak demand of 525 kW and used 190,000 kWh. What was the facility's load factor? a. 8% b. 36% C. 41% d. 49%
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- If ZTh = 3.33∠33.7 and VTh = 16.5∠33.7o V maximum power for the load will be a. 6.25 W b. 24.6 W c. 18.38 W d. 2.8 WWhat will be the value of the twiddle factor: W42An impedance coil takes 10A and absorbs 250 W when connected across a 220V, 60Hz source. What power will it absorb when connected across 110 V, 25 Hz mains? a. 539 W b. 239 W c. 439 W d. 339 W
- 30. Which are used for power factor correction in industrial applications? - a. farads b. capacitors c. watts d. coulombs7. A power station has to meet the following load demand: Load A 50 kW between 10 A.M. and6 P.M. Load B 30 kW between 6 P.M. and 10 P.M. Load C 20 kW between 4 P.M. and 10 A.M. Plot the daily load curve and determine (i) diversity factor (ii) units generated per day (iii) load factor. () 1-43 (ii) 880 kWh (iii) 52-38%]The power factor of the circuit shown in figure 2 is. a. 0.866 lagging b. 0.5 lagging c. 0.707 lagging d. 1
- An impedance of 10 + j80 ohms is connected in parallel with a 50 ohms resistor across a 230V ac source. What is the power factor of the circuit? a. 0.95 b. 0.84 c. 0.87 d. 0.92The actual impedance of a load is 10 OHM. The new per-unit impedance of the load is 0.5 pu when Base Voltage is 200 V and Base Power is O 4000 VA O 8000 VA O 6000 VA O 2000 VAThe actual impedance of a load is 10 OHM. The new per-unit impedance of the load is 0.5 pu when Base Voltage is 200 V and Base Power Is O 4000 VA CO 8000 VA O 6000 VÀ O 2000 VA