4. | sec 3B tan 3 вав 1 5. 4+x²

Q: Situation XIV: Two parallel pipes with common friction factor and length are laid. If the diameter…

A: Given that:                     40. Two parallel pipes with same friction factor and…

Q: Section 0 1 2 Remark VR (m/s) Depth (m) (degrees) - - - Right bank. 1.75 55 1.8 1.84 57 2.5 2.00 60…

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Q: Derive P = f(y) and A = f(y) for a trapezoidal channel How would you obtain y = f(Q)? 1 AR?13S/2 y b

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Q: Q.1 A line of level is run from B.M.1 (elevation=106.40m) to B.M. 2(elevation=110.50m). The field…

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Q: nd BC with bearings 58deg 30' E respec e vertex is 4+360.2

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Q: Water flows at a rate of 30m3/s in the concrete channel shown. Find the required slope of the…

A: Given:-  Water flows at a rate of 30m3/s in the concrete channel shown. Find the required slope of…

Q: J L M O N JKLMNO is an irregular hexagon. If JK = 5 m, MN = 2 m, NO = 12 m, and JO = 8 m, then 3.…

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Q: Q.I A line of level is run from B.M.1 (elevation=102.00m) to B.M. 2(elevation=106.00m). The field…

A: Given Elevation of BM1 = 102 Elevation of BM2 = 106 Reading of BS, IS and FS To Determine Computed…

Q: Assume Cd = 0.60 * 1 ft 60° 0.5 ft weir plate

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Q: spiral cu the simp

A: I= intersection angle = angle of centreR = radius of curvePI = point of intersection…

Q: 1. Uses sectioned FBDS and solves for V(x) and M(x) along segments 2 kap 18 00

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Q: 2 kN/m C 1.5 kN 5 kN/m 6 m 1m TEE 4 m 0.8 m

A: (a) ∑Fy=0; VA=0∑Fx=0; HA=2×4=8 KN∑MA=0; MA=2×4×2=16 KN-m Member Axial force diagram Shear force…

Q: Find a general solution 2" – 6z + 10z = 0

A: To find the general solution of the given differential equation (DE).   Given: z''-6z'+10z=0   The…

Q: Convert the following WCB into Reduced Bearing. • 499 • 2409 1339 • 335°

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Q: 5. Determine dz and 03. Let q = 15 kN/m and L = 6m. %3D ww

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Q: The pipe shown is subjected to the force of F = 80 lb. Determinethe angle θ between F and the pipe…

A: Angle θRBA=-2i-2j+1kRBC=-3j+1kCos θ=RBA-RBCrBArBC        =-20+-2-3+11310       = 0.7379θ=42.5°

Q: What is the true inclined distance? E = 200GPa, A = 3.0 mm² and the coefficient of linear expansion…

A: Calculation of True Inclined Length of Line  using Given Data in problem

Q: x² + y2 + z? = 21, (1, 4, 2) (b) Find a set of symmetric equations for the normal line to the…

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Q: Consider the vector V with V = 1 kN. Resolve V into components Vp along the p-axis and Vq along the…

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Q: 14. For a wide rectangular channel y>>B. a) True b) False

A: Since , AREA(A) = B.y    & Perimeter( P) = B+2y Where B>>y

Q: 8. 20 m of water (gauge) equal to psia ......... a. 43.16 b. 28.46 C. 14.05 d. None of all thes

A: Pabs=Pg+PatmPg=γwz=62.420m×3.2808ftmPg=4094.438lbft2=4094.434144psiPg=28.433psi

Q: L 0.6m 5m K-1 n-0.012 Q-18 m³/s Formulas: Rh 70- Q==AR 23S 112 n Determine the channel slope [A] use…

A: Asked: To compute the slope of the channel.   Given: Manning's roughness coefficient (n) = 0.012…

Q: 6.0 KN 1.0 m-1.0 m -4.0 m 2.0 kN/m 2.0 m B 000

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Q: 20. A trapezoidal canal, 6m at the bottom and having side slopes 2:1 carries water to a depth of…

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Q: A 2.27 m y I 1 L--x 490 N-m f 0.69 m 8 66° 0.13 0.13 1.34 KN

A: Given:- Required-To find support reactions of the given beam.

Q: Situation5. A line is recorded as 472.90 m. long. It is measured with a 0.65 kg. tape which is…

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Q: Figure No. 3 Given q = 200 N/m, L1 = 1.5m, L2 = 3m

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Q: 1. 30% Given: da = 3 m/s². same for each section Unknown: ag = ?

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Q: 13.35 kN 40° 1.22 m 1.83 m A \D 2,44 m Figure P4.137

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Q: 94 kN (b) 5@2 m = 10 m

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Q: Water Area of segment of = (1/2)r2[(T/180)0 – sine] a circle Gate ACB is in a shape of a sector of a…

A: Introduction- A circular sector, commonly defined as a circle sector or disc sector, is a closed…

Q: Compute for the Bend Allowance and K-factor. 1. 213.06 Leg Length 1 84.11 R30 BA - Leg Length 2

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Q: Q.1 A line of level is run from B.M.1 (elevation=106.40m) to B.M. 2(elevation=110.50m). The field…

A: Given B.M.1 (elevation=106.40m) B.M. 2(elevation=110.50m). To find elevation of points 2,3,4 and 5

Q: 3.5m Water 2.5m L Quarter circle shown is 3.2m long and is submerged in water. Determine d)…

A: To determine: perpendicular distance of horizontal component of hydrostatic force Fh from L, dh…

Q: Evaluate the double integral S 2 – z – y dydz. O 0.82 O 1.04 O 0.67 O 0.92

A: To evaluate the given double integral.   Given: I=∫01∫01-x22-x-y dydx

Q: Figure 03 "W, KN/m" 4.25m 5.15m b2= 0.55m b3= 0.75m "Wx1/2m, KN" h2= 0.75m h3= 0.75m 9.95m L4, m b1=…

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Q: P = 50kN P 50kN D C 2.0m 2.0m 2.0m

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Q: 3P (kN/m) C B 3m 60° 5m P (kN/m)

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Q: P(in kN) 180 KNm internal hinge 310 Nm 2.000 2 000 11m 4.000 7.000 7.500 3.500

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Q: q=66 kN/m El= 9000 kN.m2 L=4 m A EI

A: Given data: q=66 kN/mEI=9000 kN.m2L=4 m

Q: 60 kN 36 kips 26 kN/m 3.2 kips/ft C |C D 7 ft 7 ft 3 m 3 m 2 m 14 ft B.

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Q: Draw the Moment of all members.

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Q: BD = 26 mm thick %3D C = 11 mm diameler P= 29 KN O= 75° Find IC in MPa 100 mm 175 mm D 20 E 200 mm…

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Q: posite open channel of varying roughness ng roughness coefficient (ne) The vertical and slantıng…

A: According to given data

Q: Q.1 A line of level is run from B.M .1 (elevation=102.00m) to B.M. 2(elevation=106.00m). The field…

A: Given BM1=102.0m Bm2=106m To find elevation of stations 2,3,4,5

Q: Homework: Draw S.F.Ds and B.M.D 12 kN/m 40 kN В 2 m 1 m

A: As per guidelines we can solve one question at time, please upload separately,Thanks Solution to…

Q: 20. A trapezoidal canal, 6m at the bottom and having side slopes 2:1 carries water to a depth of…

A: B = 6m  Side slope 2:1 = n:1 ---> n = 2  V = 0.6 m/s

Q: -Given the following sections 1+020 a b +0.90 +3.5 +0.55 1+080 d -1.85 -1.20 -0.42 Base for cut = 12…

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Q: a height of 10 m. The H nds is 1m. The coeff to two decimal places)

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Q: P? Using appreximate hetked of analysis, find the internal forees at sec. a-a and sec.b-b and Sec.…

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