5) 2 PbS04 → IN PbSO3 + 02 Type 6) _ Al + Fe2O3 → Fe + _Al2O3 5 Type 7) SF6 → S + F2 Typ 51 D 032 8) _ C2H4 + 02 → CO₂ + _ H₂O 9) _ KClO3 → KCl + _ 02 Typ 31392 Тур 10) - Pb(NO3)2 + NaCl → NaNO3 + PbCl2 Ty 10 +8=80 = Oxygen 11) What type of = Carbon 12) Using the key provided, write the complete chemical formula show

Introduction to General, Organic and Biochemistry
11th Edition
ISBN:9781285869759
Author:Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar Torres
Publisher:Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar Torres
Chapter3: Chemical Bonds
Section: Chapter Questions
Problem 3.91P
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Question
5) 2 PbS04 →
IN
PbSO3 + 02
Type
6) _ Al +
Fe2O3 → Fe + _Al2O3
5
Type
7) SF6 → S +
F2
Typ
51
D
032
8) _ C2H4 + 02 → CO₂ + _ H₂O
9) _ KClO3 → KCl + _ 02
Typ
31392
Тур
10) - Pb(NO3)2 +
NaCl → NaNO3 + PbCl2
Ty
10
+8=80
= Oxygen 11) What type of
= Carbon
12) Using the key provided, write the complete chemical formula show
Transcribed Image Text:5) 2 PbS04 → IN PbSO3 + 02 Type 6) _ Al + Fe2O3 → Fe + _Al2O3 5 Type 7) SF6 → S + F2 Typ 51 D 032 8) _ C2H4 + 02 → CO₂ + _ H₂O 9) _ KClO3 → KCl + _ 02 Typ 31392 Тур 10) - Pb(NO3)2 + NaCl → NaNO3 + PbCl2 Ty 10 +8=80 = Oxygen 11) What type of = Carbon 12) Using the key provided, write the complete chemical formula show
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