5. Cross a Hooked Nose-tail bearing Hobbit with a heterozygous straight nosed none-tail bearing hobbit. What is the percentage of the genotype and phenotype of the offspring? What type of punnett square will you be using for this cross? Parents: Genotypes: P1 x P2 Offspring: Genotype: Phenotype:
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- 1. Complete the Punnett square for a cross between a homozygous red-flowered snapdragon (RR) and a homozygous white-flowered snapdragon (WW). Give the ratio for the phenotype and the genotype. Key F1 Genotypic Ratio: RR – red Phenotypic Ratio: wW- white RW- pink 2. Complete the Punnett Square for a cross between two Fi plants (WW). Give the phenotypic ratio for the F2 generation. F2 Phenotypic ratio: 3. Cite some possible applications of genetics to plant breeding.7. In pea plants, inflated pod is governed by a completely dominant gene and a constricted pod by a recessive gene. Another independently segregating dominant gene produces green pod while recessive gene produces yellow pod. Give the genotypes of the parents in each of the crosses given below. Phenotypes of Offspring Parental Phenotypes Parental genotypes Inflated Inflated Constricted Constricted yellow green yellow Green inflated green x inflated yellow 7.1. 58 62 18 22 7.2. constricted green x 56 18 constricted green 7.3 inflated yellow x 64 20 inflated yellow inflated green x inflated yellow 7.4. 36 38 inflated green x inflated green 7.5. 178 62 58 22What are the possible genotype and phenotype of offspring witha parent of two heterozygous tall pea plant? Legend: T- tall pea plant t- short pea plant1. Identify the genotypes of the parents 2. Complete the punnett square 3. What are the possible genotypes of the offspring. 4. What is the genotypic ration 5. What are the possible phenotypes of the offspring 6. what is the phenotypic ratio 7. What is the probability of having short trait.
- 1. Use the following information to answer the question: Parental cross is RrYy x RrYy Seed Shapes are R-round, r-wrinkled Seed colors are Y-yellow, y-green Based on the information given, what is the phenotype ratio of the offspring of this cross? 2. A pea plant heterozygous for height and seed color (TtYy) is crossed with a pea plant heterozygous for height but homozygous recessive for seed color (Ttyy). If 80 offspring are produced, how many are expected to be tall and have yellow seeds? 3. What is the chromosome theory of inheritance? How does this theory explain Mendel's results? 4. A cross between two organisms heterozygous for two different genes (AaBb) results in a 9:3:3:1 phenotype ratio among the offspring. Is the offspring's genotype ratio the same? Explain your answer.…1. The gene for tall is dominant over dwarf in the garden pea plant used by Mendel. A pea plant that comes from a line of plants that are all tall is crossed with a dwarf pea plant. What is the phenotype of the Fi generation? What is (are) its genotype(s)? Character/s: Alleles: a Genotype: 9 Genotype: Cross: Genotype/s: Phenotype/s: Genotypic Ratio: Activate V Go to Setting Phenotypic Ratio:What are the possible genotype and phenotype of offspring witha parent of two heterozygous tall pea plant? Legend: T- tall pea plant t- short pea plant 1. identify the genotypes of the parents 2. Complete the punnett square 3. What are the possible genotypes of the offspring? 4. What is the genotypic ratio? 5. What are the possible phenotypes of the offspring? 6. What is the phenotypic ratio? 7. What is the probability of having short trait?
- 3. If an individual with genotype Yy Ww Pp ee Bb is crossed with an individual with the same genotype, what proportion of offspring will have the dominant phenotype for the four heterozygous loci? answers: 81/256 81/128 27/256 3/167. In pea plants, inflated pod is governed by a completely dominant gene and a constricted pod by a recessive gene. Another independently segregating dominant gene produces green pod while recessive gene produces yellow pod. Give the genotypes of the parents in each of the crosses given below. Phenotypes of Offspring Inflated yellow Constricted yellow Parental Phenotypes Parental genotypes Inflated groen Constricted Green 7.1. inflated green x inflated yellow 58 62 18 22 7.2. constricted green x constricted green 56 18 7.3 inflated yellow x inflated yellow 64 20 74. inflated gr green x 36 38 inflated yellow 7.5. inflated green x inflated green 178 62 58 221. In pea plants, yellow color (Y) is dominant over green color (y). A yellow-colored pea plant is crossed with a green-colored pea plant. Half of their offspring is yellow-colored while the other half is green-colored.What is the genotype of the yellow-colored parent? YY O Yy yy The genotype cannot be determined. 2. A scientist discovered an unknown organism in a tropical rainforest. The organism has been identified to possess the following characteristics: (1) multicellular at some point of its life cycle; (2) feeds on decaying organic matter; and (3) has a cell wall made of chitin.Which Kingdom does the unknown organism likely belong to? Kingdom Animalia Kingdom Plantae Kingdom Fungi Kingdom Protista 3. Which statement about ferns is TRUE? Ferns are unicellular organisms. Ferns are nonvascular plants. O Ferns have spores as reproductive structures. Ferns are capable of secondary growth.
- 6. Cross a Heterozygous Green Parakeet with a white Parakeet. What is the percentage of the genotype and phenotype of the offspring? What type of punnett square will you be using for this cross? Parents: Genotypes: P1 x P2 Offspring: Genotype: Phenotype:Punnett Square Worksheet Black is the dominant fur color for rabbits and white is the recessive. B stands for the black allele and b represents the white allele. A white rabbit would have a genotype of bb and a black rabbit could have a genotype of BB or Bb. 1. Fill in the missing information for each Punnette square below: Cross 1 Cross 2 Cross 3 в B b B B Cross 4 Cross 5 Cross 6 B b b b B b B Cross 7 Cross 8 Cross 9 b Bb Bb BB Bb b Bb Bb BB Bb 2. List the probability of having black fur for each cross Cross 1: Cross 2: Cross 3: Cross 4: Cross 5: Cross 6: Cross 7: Cross 8: Cross 9: B.9. Make a pedigree for each of the following situations. For each individual, write the individual's genotype (when possible) next to the individual's symbol (e.g. O xty, I Gg): a. Two parents do not have cystic fibrosis and they have a daughter with cystic fibrosis and a son who does not have cystic fibrosis. The daughter grows up and she mates with a male who does not have cystic fibrosis. Their only child is a boy and he has cystic fibrosis. b. A man with hemophilia mates with a female without hemophilia. They have one son and one daughter. The daughter has hemophilia and the son does not have hemophilia. The son grows up, and he marries and mates with a female. Their only child is a boy, and he has hemophilia.