5. Given a balanced 3-ph 34.64 kV system serving a 120 MVA unity pf load, which can be modelled as balanced 3-wirewve-connected impedances. XZy = (346420° +34642-120° +34642120°)(a) Find Ży.LOKR(120)(b) If = 34.64 kV and SLBaseVa=34.64x-150-10 MVA find V, and Z, in pu.Zu 600VúZy = V₁²538= 102

In this question, we need to determine load impedance, per unit voltage and per unit impedance. We…

5. Given a balanced 3-ph 34.64 kV system serving a 120 MVA unity pfload, which can be modelled as balanced 3-wire Zy = (346420° +34642-120° +34642120°) (120) 2 wve-connected impedances. (a) Find Z,. сока -15 (b) If = 34.64 kV and S-10 MVA find V, and Z, in pu. LBase Va= 34.64 7X Zu 600 = 538 = 10

5. Given a balanced 3-ph 34.64 kV system serving a 120 MVA unity pfload, which can be modelled as balanced 3-wire Zy = (346420° +34642-120° +34642120°) (120) 2 wve-connected impedances. (a) Find Z,. сока -15 (b) If = 34.64 kV and S-10 MVA find V, and Z, in pu. LBase Va= 34.64 7X Zu 600 = 538 = 10

Power System Analysis and Design (MindTap Course List)

6th Edition

ISBN:9781305632134

Author:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma

Publisher:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma

Chapter2: Fundamentals

Section: Chapter Questions

Problem 2.14MCQ: The instantaneous power absorbed by the load in a single-phase ac circuit, for a general R LC load...

See similar textbooks

Similar questions

6.5% ans ex A so kvA. 2o00/20 V, So He single-phase transformar has impedance drof of8% and resistance drop of 4%. Caleulate. The Requlation of the Thams former at full- Load o8 P.s Legging. also find The Power factor at which Voltage requlation will Be Zero. Sols 0.5 leading. s alculate The % Noltege Requlation af atransformar in w hich the Percantage resistance drof is 1% and Percentage dre is 6% when The Power fador is 0.8 lagging ) > unity aMS 38 % ans 1 % (シ→ 0.8 leading . amS - 2.2%
2. Two transformes A and B of ratings 5uokVA and 25okVA. Supplying a load kVA of 750 ato.8Pf lagging. open circunt valtajes are 400V and 410v respectively. Trusfarmn A has 1/ nsistance and 5/ ractance and traugformer B hay 1.$, mesistona and 41 reactance. Find (^) Crossacarent in the seandaries on no.load.ib) the load shared by euch transfarmer Their are
VASSESSMENT PROBLEM Objective 5-Be able to analyze circuits with ideal transformers 15 The source voltage in the phasor domain circuit in the accompanying figure is 25 /0° kV. Find the amplitude and phase angle of V2 and I2. 1.5 kn j6 kN 25:1 V2 --j14.4 N V, Ideal
Explain current divider rule in ac circuits with two parallel impedances Z1 and Z2. Calculate the currents I1 and I2 in phasor form for the circuit given in figure.
A star connected load with real impedance ZL= 1-j1 Ohm per phase is connected to the secondary of a three-phase Ynyn0 connected transformer. The equivalent impedance per reduced phase of the transformer to the primary is Zeq1= 1+j5 Ohm. The nominal primary voltage is V1Ln= 5920 V and the conversion ratio is a= 10. what is the amplitude of the actual voltage falling on one phase of the specified load? (simplified equivalent circuit will be used).
(b) A symmetrical delta-connected 415V three-phase supply is feed to an asymmetrical delta- connected load as shown in Figure Q2(b). Assume that it is a RYB sequence. The impedances of the load are ZRY = 50 +j50 Q , ZYB = 150 + j0 Q and ZBR= 50 – j50 N. (i) Determine and draw the phasor diagram of phase currents in the load. (ii) Determine and draw the phasor diagram of line currents in the system.
A parallel connection of a RL branch with a C branch is connected across a 100V AC mains. At first R = 10 ohms, L = 20mH and frequency of 1000rad / s, the current measured is 2.2361A at 89.44 leading power factor. A) Determine the initial capacitance. B) However, a fault occurs on the capacitor branch making its capacitance 20% lower and a resistance of 5 ohms is detected. If this faulty circuit is rerun but at a frequency of 500 rad / s, determine the new current that will flow through the circuit.
One side of a transformer has What is the voltage (in V rms) at the secondary? 1,800 turns while the other side has 450 turns. The high voltage side is connected to a 240 Vrms source. The low What is the current (in A rms) at the secondary? What is the current (in A rms) out of the source? What is the value of the load impedance when referred to the primary? • Referred impedance = voltage side (secondary) is connected to an impedance ZL = 20 + j10 Q. Provide at least 4 digits after the decimal point. +j_ N What is the value of the source voltage (in V rms) when referred to the secondary?
Please help with this balanced three-phase circuit problem.
D = 0.9 1.5° and B = 150 65° has at the load end a The load voltage and current are V₁ and I₁ A' B' VL B][Y and evaluate these constants. C' D' IL A long line with A transformer having series impedance Zr Obtain expression for Vs and Is in the form 10067°. [$]-[ =
A 50 Hz, Scott connected transformer supplies an unbalanced two phase load at ( 400 V) per phase. For the leading phase the load has a resistance of (13.3 ohm) and capacitor of (318) micro farad in series. For the other phase the load consists of resistance (10) ohm and an inductance of (42.3) mH. Calculate both mathematically and graphically the lines currents on 3 phase side. The main transformer primary to secondary turns ratio is (12/1).
In the figure, bus 1 is the reference bus, V1 = 1.06 p.u and the angle is 0.. A load with active power= 100 MW and reactive power = 50 Mvar is connected to bus 2. The line impedance is z12 = 0.12 + j0.16 p.u on a base of 100 MVA. Start with an initial estimate of |V2|0) = 1.0 p.u and 820) = 0•. Find |V2| () (one iteration). 100 MW 212 = 0.12 + j0.16 ++ 50 Mvar Vị = 1.0/0° О а. |V2| (1) = 0.4 p.u. Ob. |V2| (1) = 0.5 p.u. Oc. |V2| (1) = 0.7 p.u. d. (1) = 0.8 p.u. е. |V2| (1) = 0.6 p.u.