6 lim Sinx ex -1

Q: 1 lim X→0 SIN²X SINX x2

A: Note:- We’ll answer the first question since we answer only one question at a time. Please submit a…

Q: 1-cos x lim sin x x→0

A: Given: limx→01-cosxsinx

Q: х-tanx 2. lim х30 1-со 3 3. lim sinx lnx = 0 x→0+

A:

Q: Lim Sinx 2x メ→0

A: lim (x->0) sinx/2x

Q: limx→0  (x^2+3) / (1−cosx)

A: given example is, limx→0x2+31-cosx

Q: -1 sin (5x) lim

A: The given expression is limx→0sin-15xx the given expression is the indeterminate form 00 Apply L'…

Q: 2 xt (* sin) lim sec x lim X→+0 X. 2

A: Given limits are  1) limx→∞xsin2x2)limx→π2secx3)limx→0sinxx

Q: Sinx lim Cos 1-

A:

Q: Find an equation of the tangent line at x = 0. y = x5 + cos(x) .13 (Use symbolic notation and…

A: We have given equation  y=x13+cosx Put x=0  y=0+cos(0)=1 Point on the curve x1,y1=0,1…

Q: sin 5x lim, X→0

A: Given, limx→ 0sin5xx   Apply the L'Hopital's Rule: limx→ 0sin5xx=limx→ 0cos5x· 51

Q: T-cosx 2. limx-0 3.limx-0 sinx x2 +1 4.limx-0 x+cosx

A: Since you have posted a question with multiple sub-parts, we will solve first three subparts for…

Q: 1. lim sin -;). x→2

A: Dear student as per our rule in one session we can only solve one question. Please post the other…

Q: 33. lim x→0 x – sinx

A: We’ll answer the 33th question since we answer only one question at a time. Please submit a new…

Q: x+2 lim sin - x+6x+8 3 2.

A:

Q: sin°(,² – 4) (x+2) tan(x+ 2 limy→-2

A: We have to solve

Q: 43. lim x sin(7/x) 45. lim sin 5x csc 3x

A:

Q: 2. sinx+4 sin x-5 lim sin x-1 Xx/2

A: →When limit is of the form 00 or ∞∞, then L Hospital's rule is used. In this rule, take the…

Q: tan (3x) lim x→0 sin (2x)

A: Given query is to find the limit of the expression.

Q: In(sin 4x) \ In(sin 8x) lim x → 0

A: We have to evaluate the limitlimx→0ln(sin4x)ln(sin8x)

Q: x + sin 2x lim x-2 x – sin 2x О з O 2 O 1/3 О 12 O other:

A:

Q: lim sin(5x) csc(3x) X-0

A: Formula: LimX→0[sin(ax)/x]=a

Q: lim sin(1/r),

A: We have to find limit

Q: 61. lim r sinx 63 1:

A:

Q: 2 sin x 1 lim is

A:

Q: 4x+sin x lim x→02x - sin 3x

A: We have to solve given problem:

Q: 3 lim z? sin(-

A:

Q: (sinx -) (3sin²x -sinx +1) lim TE +X, 2

A:

Q: 2x sin-1 lim х30 еx — х — 1

A:

Q: (7x – 10,* lim x+0 7x lim 2x sin- 9 sin 27x lim x2 21x lim x+00 12 – 3x

A:

Q: 2 sin a-sin 2x limr x-sin x

A: use l hospital rule

Q: 2. lim x sin(1/x) X18 ex+2x 3. lim X18 ex

A:

Q: cosxsin2x lim 1-sinx x- 2

A: limx→π2cos x sin2x1- sinx=limx→π2cos x 2 sinx cosx1 - sinx=limx→π22 cos2x  sinx1 - sinx…

Q: 2) lim sin 4x

A:

Q: Find the limit

A:

Q: lim x approches 0 of sin(5x)/7x

A: We have to calculate; A=limx→0sin(5x)7x

Q: 2. Evaluate cosxsin2x lim 1 – sinx

A: We need to find limx→π2cos x sin 2x1-sin x Now, put the limit in the function, that is put x=π2 .…

Q: 44. lim sin² x 7/4

A: The limit is, 1/2 The detailed solution is as follows below :

Q: 6. lim (sinx)*

A: u =eln u, then:limx→0+  (sin x)x  =limx→0+  ex ln(sinx)=limx→0+  eln(sinx)1x=elimx→0+  ln sin(x)1x

Q: 4. lim (sinx)tanx X0+

A:

Q: 4 lim sin(x) х>0 х 41

A: Given that

Q: 2 sin x lim In

A:

Q: 1 lim x-0 (sinx ズ→ X.

A: Evaluate the limit limx→01sin x-1x. Rewrite the expression: limx→01sin x-1x=limx→0x-sin xx sin x…

Q: tanx – lim 0 Cos[1 – –

A: Given, -limx→0cos1-tanxx

Q: 5 sin(6x) lim x→0 3x

A:

Q: х(4+sin 6x) 3. lim X→+0 х+1

A:

Q: o( san(s) sin(2x) + lim X 0 cos (x) × 6

A:

Q: 1 (sinx\1-cosx lim X→0

A: We need to evaluate limx→0sin xx11-cos x Let y = sin xx11-cos x Then log y = 11-cos x log sin x…

Limits

When it comes to calculus, limits are considered to be a very important topic of discussion. The main importance of limit lies in expressing the value of a function as it gets closer to a certain value. Also, limits can help you to understand other topics, such as continuity and differentiability better. In a broader sense, every calculus notion is a limit. Other branches of calculus have also been derived from limits.