Which of the following strains below are defective in the same gene as strain M? Answer yes if the strain is defective or no ifit is not.Strain DefectiveGKWTMAOC→(→◆N/A<><><> Eight mutant bacteriophage strains cannot lyse a certain type of bacteria that can be lysed by wild-type bacteriophages. Themutant strains were allowed to infect the bacteria in a complementation test. A "+" indicates that lysis occurred withcoinfection. A "-" indicates that lysis did not occur.GKWTMAQCG- ++++-KWTMAQC- + +++-++++- + +-+- +--+ ++A cistron is defined by no complementation in theHow many genes are controlling lysis in this bacteriophage? (Use a number not a word in the space)configuration.

In a complementation chart a group will contain similar mutations that failed to compliment one…

Answered: 6 = W - 1 A 2 C ♦ ( ◆ ♦ N/A (> ◆ ◆

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6 = W - 1 A 2 C ♦ ( ◆ ♦ N/A (> ◆ ◆

Human Anatomy & Physiology (11th Edition)

11th Edition

ISBN:9780134580999

Author:Elaine N. Marieb, Katja N. Hoehn

Publisher:Elaine N. Marieb, Katja N. Hoehn

Chapter1: The Human Body: An Orientation

Section: Chapter Questions

Problem 1RQ: The correct sequence of levels forming the structural hierarchy is A. (a) organ, organ system,...

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Eight mutant bacteriophage strains cannot lyse a certain type of bacteria that can be lysed by wild-type bacteriaphages. The mutant strains were allawed to infect the bacteria in a complementation test. A "+ indicates that lysis occurred with coinfection.Aindicates that lysis did not occur. GKWTMAQC G -++|+ ++l+ - K. - + - ++ +| + -+| - |-++ + + + M - + + + A cistron is defined by no complementation in the Ciş : configuration. Haw many genes are controlling lysis in this bacteriophage? (Use a number not a word in the space) 3 Which of the following strains below are defective in the same gene as strain Q? Answer yes if the strain is defective or no if it is not. Strain Defective A N/A
Shown below are the complementation test results involving 4 independently isolated lethal mutants in a bacteriophage. Complementation was assayed by simultaneouly infecting bacteria with two phage strains, each with a different mutation, neither of which could alone lyse the cells. In the table below, a "+" indicates the strains complemented each other and therefore lysed open the bacteria. A "0" indicates no complementation and therefore no cell lysis occurred. Test pair Results 1___2___3___4 1,2 + 1 0 + + 0 1,3 + 2 0 + + 1,4 0 3 0 + 2,3 + 4 0 2,4 + 3,4 + How many genes are there? a. 3 b.1 c. 2 d. 4
Shown below are the complementation test results involving 4 independently isolated lethal mutants in a bacteriophage. Complementation was assayed by simultaneouly infecting bacteria with two phage strains, each with a different mutation, neither of which could alone lyse the cells. In the table below, a "+" indicates the strains complemented each other and therefore lysed open the bacteria. A "0" indicates no complementation and therefore no cell lysis occurred. Test pair Results 1___2___3___4 1,2 + 1 0 + + 0 1,3 + 2 0 + + 1,4 0 3 0 + 2,3 + 4 0 2,4 + 3,4 + Which mutants are in the same gene? . a. 2, & 3 b.1, 2, 3 & 4 c.1 & 4 d.1, 2 & 4
You are given two strains of E. coli. The Hfr strain is arg+ ala+ glu+ pro+ leu+ T s; the F− strain is arg − ala− glu− pro−leu− T r. All the markers are nutritional except T, which determines sensitivity or resistance to phage T1. The order of entry is as given, with arg+ entering the recipient first and T slast. You find that the F− strain dies when exposed to penicillin (pens), but the Hfr strain does not (penr). How would you locate the locus for pen on the bacterial chromosome with respect to arg, ala, glu, pro, and leu? Formulate your answer in logical, well-explained steps, and draw explicit diagrams where possible.
Austin Taylor and Edward Adelberg isolated some new strains of Hfr cells that they then used to map several genes in E. coli by using interrupted conjugation . In one experiment, they mixed cells of Hfr strain AB-312, which were xyl+ mtl+ mal+ met+ and sensitive to phage T6, with F− strain AB-531, which was xyl− mtl− mal− met− and resistant to phage T6. The cells were allowed to undergo conjugation. At regular intervals, the researchers removed a sample of cells and interrupted conjugation by killing the Hfr cells with phage T6. The F− cells, which were resistant to phage T6, survivedand were then tested for the presence of genes transferred from the Hfr strain. The results of this experiment are shown in the accompanying graph. On the basis of these data, give the order of the xyl, mtl, mal, and met genes on the bacterial chromosome and indicate the minimum distances between them.
A researcher is studying the r// locus of phage T4. Three //-- strains are obtained: A, B, and C. E. coli strain K(A) is coinfected with two rl strains simultaneously and the results are recorded. Infection with A and B phage = lysis occurs Infection with A and C phage = lysis occurs Infection with B and C phage = no lysis occurs What can be inferred from this complementation test? Multiple Choice Strains A, B, and C have mutations in three different genes. Strains A and B have mutations in the same gene, and strain C has a mutation in a different gene. Strains A and C have mutations in the same gene, and strain B has a mutation in a different gene. Strains A, B, and C have mutations in the same gene. Strains B and C have mutations in the same gene, and strain A has a mutation in a different gene.
Before development of a vaccine against this microbe, thedisease it caused accounted for two-thirds of bacterial meningi-tis cases during the first year of life but is still the number oneleading cause of mental retardation in patients who survive seri-ous disease due to permanent central nervous system disorders.What is the microorganism?(a) Haemophilus influenzae type B(b) Haemophilus influenzae type A(c) Neisseria meningitidis(d) Streptococcus pneumoniae(e) Listeria monocytogenes
You are a graduate student working to construct a single gene knockout library of Leptospiria kirschneri, one the causative agents of leptospirosis. You are looking for single gene mutants which disrupt the bacterium’s spirillum shape to determine what role this rare cellular morphology may play in disease development and progression. Using an appropriate donor strain, you introduce the plasmid shown into L. kirschneri. L. kirschneri is not able to replicate the plasmid. The repeat regions are denoted on the plasmid map as vertical black lines, the transposase is denoted as tnp, and kanamycin kinase is denoted as aph. The larger of the two regions is transposed. Following selection and counter-selection, you isolate several non-spirillum colonies, which you use to infect juvenile piglets. Most of the infected piglets develop leptospirosis. Isolating L. kirschneri from these animals reveals that it has regained its spirillum morphology. What is a likely explanation for this reversion of…
Which of the following is in the correct order heme --> biliverdin --> bilirubin --> urobilins heme --> bilirubin --> biliverdin --> urobilins biliverdin --> heme --> bilirubin --> urobilins biliverdin --> bilirubin --> transferrin --> urobilins Ood
In 1944, Avery, Macleod, and McCarty provided strong evidence that DNA is the hereditary material in Streptococcus pneumoniae by Group of answer choices showing that avirulent cells could become virulent by the process of transduction none of these is true. showing that virulent cells could become avirulent if the DNA was destroyed after transformation showing that avirulent cells could not gain the ability to become virulent cells if conjugation was interrupted. showing that avirulent cells could not gain the ability to become virulent if DNA was destroyed after transformation.
You are counting plaques on your plaque assay plates made from serial dilutions of your high titer lysate. Your 10-5 plate has 615 plaques although some are butting up against each other so it is difficult to get an accurate count. Your 10-6 plate has 42 plaques, and your 10-7 plate has only 1 plaque. Which plate would probably yield the most accurate titer calculation of your phage and why is it more trustworthy than the others?
Austin Taylor and Edward Adelberg isolated some new strains of Hfr cells that they then used to map several 200 mal+ genes in Escherichia coli by using interrupted conjugation. 150 In one experiment, the researchers mixed cells of Hfr strain AB-312, which were xyl* mtl* mal* met* and sensitive to phage T6, with F strain AB-531, which was xyl mtl mal met and resistant to phage T6. The 100 mt/+ cells were allowed to undergo conjugation. At regular intervals, the researchers removed a sample of cells and 50 met+ interrupted conjugation by killing the Hfr cells with phage T6. The F cells, which were resistant to phage T6, survived and were then tested for the presence of 0. 20 40 60 80 100 genes transferred from the Hfr strain. The results of this experiment are shown in the graph. Time of sampling (minutes) On the basis of these data, give the order of the xyl, mtl, mal, and met genes on the bacterial chromosome and the minimum distances between them in minutes. The origin of transfer is…