6. |(a) (i) Draw the logic diagram of the following Boolean expression (1 mark) X = (A + AB)(AB + B) (ii) Simplify the above Boolean expression(1 mark) (iii) Draw the logic diagram after the simplification. (1 mark)
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- Draw the logic circuits for the following Boolean expressions and simplify the logic expressions using theorems of Boolean algebra. (Ā+B)(A+ Ē + D)DTask 6: Simplifying Boolean functions in EWB using the logic converter Simplify the following Boolean expression in EWB using the logic converter F (A, B, C) = AB'C'+ A'B'C'+ A'BC'+ A'B'CA three input logic functipn will provide a logic high output only when twp (and two only) of the inputs are logic highs. For all other input possibilities, a logic zero is provided on the output. What is the logic expression? A. Y=A'B'C+A'BC'+AB'C' B. Y=AB'C+A'BC+ABC' C. Y=AB'C+ABC+A'B'C' D. Y=ABC'+AB'C+A'B'C'
- Basic Combinational Logic Circuits 2. Write the output expression for logic circuit: A B B Xii) For the circuit shown in Figure B9, a. Find logic functions for Y and Z. b. Simplify function Z using Boolean algebra. Y Figure B9 AB2.1 Combinational logic circuits. Tabulates a truth table for the following Boolean expression shown in Equation 1.1. f = A.B.C + A.B.C + A.B.C (1.1) 2.2 Half adder. A half adder is a circuit that adds two binary digits, A and B. It has two outputs, sum (S) and carry (C). The carry signal represents an overflow into the next digit of a multi-digit addition. Figure 1.2 depicted a logic diagram for a half adder. a. derives the Boolean expression for s and c. b. tabulates a truth table for the half adder. Ao Bo Figure 1.2: Half adder os S C
- Simplify by using Boolean algebra (show all the steps)Q.No.10: Draw Combinational Logic Circuit for the following Boolean expression i.e. one combine circuit for each expression? *Then simplify and prove the problems i.e. Boolean expression using Boolean rules and laws as discussed in the class. E.g. prove it with the help of Boolean rules and law that B+BC=B, how? (i) B+BC=B (ii) B+BC=B+C (iii) (B+C)(B+D)=B+CDDraw the logic circuit for F=A.(B+C) .
- (a) Identify the static hazards in the following logic functions and draw the hazard free logic circuit diagrams. Your answer should include separate Karnaugh maps for with and without hazards. A is defined as the MSB. f = Ā. B.D + (C + D)(B+T)Design the following combinational logic circuit with a four-bit input and a three-bit output. The input represents two unsigned 2-bit numbers: A1 A0 and B1 B0. The output C2 C1.C0 is the result of the integer binary division A1 A0/B1 B0 rounded down to three bits. The 3-bit output has a 2-bit unsigned whole part C2 C1 and a fraction part CO. The weight of the fraction bit CO is 21. Note the quotient should be rounded down, i.e. the division 01/11 should give the outputs 00.0 (1/3 rounded down to 0) not 00.1 (1/3 rounded up to 0.5). A result of infinity should be represented as 11.1. A minimal logic implementation is not required. (Hint: start by producing a truth table of your design).1.Simplify: (A + C)(AD + AD) + AC + C to its simplest logic function and create a logic diagram 2, Simplify: A(A + B) + (B + AA)(A + B) to its simplest logic function and create a logic diagram 3. Simplify: AB(A+ B)(B+ B) to its simplest logic function and create a logic diagram