67. = 2x − 7, y(2) = 0 dy dx dy 68. = 10 - x, y(0) = -1 dx 1 69. dx + x, x > 0; y(2) = 1

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter2: Equations And Inequalities
Section2.3: Quadratic Equations
Problem 82E
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Related questions
Question
Q. 67-75 Solve the initial value
problems.
dy
67.
2 – 7, y(2) = 0
dx
68.
10 - x, y(0) = -1
dx
dy
69.
-
+ x, > 0; y(2) = 1
dx
1-²
dy
70.
==
9x² - 4x + 5, y(-1) = 0
dx
dy
71.
= 3x-2/3, y(-1) = -5
dx
dy
1
72.
-
y (4) = 0
dx
2Vx
ds
73. = 1 + cost, s (0) = 4
dt
74.
= cost + sint, s(7) = 1
-π sin 70, 7(0) = 0
1. / 126 +
=
=
ds
dt
dr
75.
d0
Evaluate the integrals in Exercises 13-36.
13.
·/₁
V3-2s ds
14.
(2x + 1)³ dx
Area
In Exercises 37-42, fine
x-axis.
|37. y = -x − 2x, -
38. y = 3x²-3, -25
39. y=x²-3x² + 2
40. y = x² - 4x. -2
41. y = x¹/³, -1 s
42. y = x¹/3 - x, -
9. (a) Find the termi
is (1, -2).
(b) Find the initi
point is (5, 0.
10. (a) Find the terr
is (2, -1).
(b) Find the ter
point is (-2
11-12 Perform the
and w.
11. u = 3i - k, v
(a) w - v
(c) -v - 2w
(e) -8(v + w
12. u = (2,-1,3
(a) u - w
Transcribed Image Text:Q. 67-75 Solve the initial value problems. dy 67. 2 – 7, y(2) = 0 dx 68. 10 - x, y(0) = -1 dx dy 69. - + x, > 0; y(2) = 1 dx 1-² dy 70. == 9x² - 4x + 5, y(-1) = 0 dx dy 71. = 3x-2/3, y(-1) = -5 dx dy 1 72. - y (4) = 0 dx 2Vx ds 73. = 1 + cost, s (0) = 4 dt 74. = cost + sint, s(7) = 1 -π sin 70, 7(0) = 0 1. / 126 + = = ds dt dr 75. d0 Evaluate the integrals in Exercises 13-36. 13. ·/₁ V3-2s ds 14. (2x + 1)³ dx Area In Exercises 37-42, fine x-axis. |37. y = -x − 2x, - 38. y = 3x²-3, -25 39. y=x²-3x² + 2 40. y = x² - 4x. -2 41. y = x¹/³, -1 s 42. y = x¹/3 - x, - 9. (a) Find the termi is (1, -2). (b) Find the initi point is (5, 0. 10. (a) Find the terr is (2, -1). (b) Find the ter point is (-2 11-12 Perform the and w. 11. u = 3i - k, v (a) w - v (c) -v - 2w (e) -8(v + w 12. u = (2,-1,3 (a) u - w
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