7. A differential leveling loop is run from an established BM to a point 9.66 Km away, with a misclosure of 22.25 mm. What order levelling does this represent? Circle all that apply SHOW ANY CALCULATIONS YOU MAKE Order Class Maximum closure a. First Order, Class I First 4 mm VK b. First Order, Class II 11 5 mm VR c. Second Order, Class I Second mm VK d. Second Order, Class II %3D 8 mm VK Third 12 mm VK e. Third Order

7. A differential leveling loop is run from an established BM to a point 9.66 Km away, with a misclosure of 22.25 mm. What order levelling does this represent? Circle all that apply SHOW ANY CALCULATIONS YOU MAKE Order Class Maximum closure a. First Order, Class I First 4 mm VK b. First Order, Class II 11 5 mm VR c. Second Order, Class I Second mm VK d. Second Order, Class II %3D 8 mm VK Third 12 mm VK e. Third Order

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Similar questions

A differential levelling circuit began on BM Mil and closed at BM Oak with the elevations indicated in the figure below. The plus sight and minus sight distances were kept approximately equal. Readings (in feet) are described below. Prepare, Check and adjust the notes. BM Mill Eleviz 2053.18 1.33 HI=2054.51 8.3 тр1 0,22 HI=2046.36 7.91 TP2 0.96 11.72 0.46 TP3 Mean sea level 8.71 BM Oak
C ... 1m 6m A 30° Water Area of segment of = (1/2)r²[(n/180)0 – sine] a circle %3D Gate ACB is in a shape of a sector of a circle whose radius is 6m as shown. Determine the following: a) Horizontal component FH is Blank 1 KN b) Vertical component Fv is Blank 2 KN c) Distance of FH from point "C" is Blank 3 m c) Distance of Fv from point "C" is Blank 4 m B.
Q#1: A profile levelling is carried out and consecutive readings were observed on staff rod along a chain line at common interval of 10 meter which are listed below in table. First reading is taken on bench mark of 105.615 meter reduce level. Station Points Chainage (m) Staff Readings (m) Remarks BS IS FS 1 00 3.005 BM 2 10 2.285 3 20 1.560 4 30 1.785 5 40 2.105 6 50 2.875 3.105 CP 1 X 53.35 3.465 7 60 3.955 8 70 3.120 9 80 3.015 10 90 2.580 11 100 1.955 CP 2 Determine the reduce levels of all points using both line of collimation and rise and fall method. (Present your answer in table form).
The accompanying schematic arrangement of line portray a differential level route. Th values indicated represent back-sight and foresight readings taken at different points as labelled. Prepare the complete differential level notes for the information shown and the customary arithmetic check. STA. BS HI FS ELEV. BM1 2.35 356.65 TP1 1.37 3.28 TP2 3.08 2.04 ТРЗ 1.54 3.61 ТР4 0.85 3.69 BM2 3.07 Arithmetic Check: Elevation BM1+(SUMMATION OF BS) -(SUMMATION OF FS) =BM2 A. Height of the instrument at TP4. B. Elevation of TP4. C. Difference in elevation of TP1 and TP4.
Meet - nzw-pimo-rw anuwwlPx-a_a7HdrtDNnmaFDF2GGA/formResponse none of the above. O To establish a new benchmark on point Busing a levelling instrument. The work had been done between B.M1 and B.M2 to the required point B, and the observations were recorded as in the tables below. Calculate the best value *of elevation for point B B.M1 B B.M2 B BS Point B.M1 T. P1 BS FS 3.305 Remarks RL-34.585 FS 0.405 4.24 3.35 Point Remarks B 30.06 0.672 1.825 2.485 3.315 1.23S 3.715 T. P4 T. PS B.M2 1.795 A 4.01 3.485 Т. Р2 T. P3 3.315 2.78 RL=42.093 B 39.97m 41.97m 46.97m 45.98m O 44.37m O 40.95m O * Reciprocal ranging is employed when one end of a line is inaccessible. O the ends of the line are not visible even from intermediate points. O both the ends are inaccessible. the two ends of a line are not intervisible,O O O O O O O O O O OC
B. Double-Rodded Leveling 3. Complete differential level notes for the information shown and perform the customary arithmetic check. STATION BS HI FS STATION 1.722 BM1 127.378 m 1.722 ΤΡΙΗ 2.623 1.382 TP1L 2.789 1.522 TP2 H 3.089 0.899 TP2 L 3.214 0.714 ТРЗ Н 1.521 2.452 TP3 L 1.632 2.678 ТРА Н 2.333 1.113 TP4 L 2.589 1.523 TP5 H 0.667 2.877 TP5 L 0.986 2.543 3.521 BM2 3.214
Q3: A: Draw the diagram of traverse classification. B: In closed traverse ABCD. The partial coordinates were known as shown below. Determine its area by DMD method. 04 N Dofland OWODY dienstl it with (nm) dinostim Mem. AB BC CD DA ΔΧ 40 -80 -50 AY 60 100 -70
DIFFERENTIAL LEVELING. Complete the differential level notes shown below and perform the customary arithmetic. STA BS HI FS ELEVATION ВМ10 2.085 137.450 m ТР1 2.015 0.982 ТР2 1.864 1.428 ТРЗ 0.579 1.527 BM11 0.423 2.423 TP4 1.446 1.807 ТР5 1.778 1.725 ТР6 2.051 2.339 TP7 2.920 1.005 ВМ12 3.186 2.358 ТР8 2.805 0.995 ТР9 0.774 1.206 ВМ13 0.603
Q2/ Complete the settlement table below and verify the correctness of the calculations. Then check the correctness of the work, bearing in mind that the length of the leveling line is 2,250 meters, bearing in mind that the required level of leveling is the third. Find the closing error and adjust the levels if necessary, suppose that the error equal for all points. Elevation Station B.M1 TP1 TP2 TP3 TP4 TP5 TP6 BM1 B.S 1.23 0.955 1.332 1.652 2.558 2.465 2.882 H.I F.S 1.735 2,642 3.000 2.524 2.221 0.755 0.218 50,000
Given the three-wire leveling note below, find the elevation of BM2 and perform the customary arithmetic check. Sta BM1 TP1 TP2 TP3 BM2 Hair Rgds 1.152 0.935 0.718 1.713 1.440 1.167 2.784 2.350 1.916 0.913 0.730 0.547 Backsight Mean Rgds (#1) (#4) (#7) S (#2) HI (#3) Hair Rgds Foresight Mean Rgds S 1.177 0.899 0.621 1.905 1.537 1.169 1.450 1.177 0.904 2.210 1.714 (#8) (#9) 1.218 (#5) Elev 450.545 (#6) (# 10)
Q3: Calculate the true differenc between points (A&B), then correct the staff reading at point (B) were the level instrument near (A). Level Instrument Position Reading at (A) Mid. point Near A 1.465 1.540 Reading at (B) 1.350 1.409
SURVEYING Given the following differential level notes: STA BS FS BM1 1.73 - TP1 2.5 3.8 TP2 2.75 1.7 BM2 3.15 3.32 TP3 2.45 3.22 TP4 3.9 2.5 TP5 2.78 3.02 BM3 - 1.77 Base on the differential leveling of note in the previous problem, if the elevation of TP3 = 267.28 m, determine the elevation of BM1