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- Pd Pd 1. Let's consider a toy model of nuclear fission. Suppose an nucleus of Uranium-235 (92 protons, molar weight of 235 g/mole) "splits" into two "daughter" nuclei of Palladium (46 protons each) – this is not how it really happens, but it's a very simple model that actually gives fairly accurate results. The radius of the original U-235 nucleus is about 7.4 x 10-15 m. (a) If the Pd nuclei each have half the volume of the U nucleus, which is reasonable, and they are "touching" right after the split, how far apart are their centers? (b) Using conservation of energy, what will be the sum of the kinetic energies of the Pd nuclei when they are far apart from each other? (c) That's energy of one atom undergoing fission, so what, then, is the energy released by the fission of 1 kg of U-235? Express this in Joules and also in kilotons of TNT, where 1 kt = 4.2x1012 J. (The Hiroshima bomb yielded about 15 kt) (d) How many kwh (kilowatt-hours) of energy is this, (1 kwh = 3.6x10° J), and (if…The nucleus of an atom can be modeled as several protons and neutrons closely packed together. Each particle has a mass of 1.67 x 10-27 kg and radius on the order of 10-15 m. (a) Use this model and the data provided to estimate the density of the nucleus of an atom. | kg/m³ (b) Compare your result with the density of a material such as iron w = 7874 kg/m?). What do your result and comparison suggest about the structure of matter?1:54 O KB/S ul . 52 %3D s the the g With a wooden ruler, you measure the length of a rectangular piece of sheet metal to be 16 mm. With micrometer calipers, you measure the width of the rectangle to be 8.98 mm. Use the correct number of significant figures: What is (a) the area of the rectangle; (b) the ratio of the rectangle's width to its length; (c) the perimeter of the rectangle; (d) the difference between the length and the width; and (e) the ratio of the length to the width? Your answer
- The nucleus of an atom can be modeled as several protons and neutrons closely packed together. Each particle has a mass of 1.67 x 10-27 kg and radius on the order of 10-15 m. (a) Use this model and information to estimate the density of the nucleus of an atom. 3.986E177 Your response differs significantly from the correct answer. Rework your solution from the beginning and check each step carefully. kg/m³ (b) Compare your result with the density of a material such as iron. What do your result and comparison suggest about the structure of matter?A proton, which is the nucleus of a hydrogen atom, can be modeled as a sphere with a diameter of 2.4 fm and a mass of 1.67 10-27 kg.Densities of Some Common Substances at Standard Temperature (0°C) and Pressure (Atmospheric) Substance ρ (kg/m3) Substance ρ (kg/m3) Air 1.29 Iron 7.86 ✕ 103 Air (at 20°C andatmospheric pressure) 1.20 Lead 11.3 ✕ 103 Aluminum 2.70 ✕ 103 Mercury 13.6 ✕ 103 Benzene 0.879 ✕ 103 Nitrogen gas 1.25 Brass 8.4 ✕ 103 Oak 0.710 ✕ 103 Copper 8.92 ✕ 103 Osmium 22.6 ✕ 103 Ethyl alcohol 0.806 ✕ 103 Oxygen gas 1.43 Fresh water 1.00 ✕ 103 Pine 0.373 ✕ 103 Glycerin 1.26 ✕ 103 Platinum 21.4 ✕ 103 Gold 19.3 ✕ 103 Seawater 1.03 ✕ 103 Helium gas 1.79 ✕ 10−1 Silver 10.5 ✕ 103 Hydrogen gas 8.99 ✕ 10−2 Tin 7.30 ✕ 103 Ice 0.917 ✕ 103 Uranium 19.1 ✕ 103 (a) Determine the density of the proton.kg/m3Weight of the ozone layer 1.0p 1 Incredibly, the ozone layer in the upper atmosphere that protects us from the ultraviolet rays of the Sun varies somewhat but, on the average, would be less than one centimeter thick if it were brought down to sea level. Given that the density of ozone at sea level would be about 2.0 grams per litre, what is the total amount of ozone (in Tonnes) in the upper atmosphere when its sea-level thickness is 0.22 cm? Take the radius of the Earth to be 6400 km. (The volume of a thin skin around an object is the surface area of the object times the skin thickness.) Give your answer in gigatonnes, and do not specify units in the answer box. Answer Show feedback Updated just now 4
- The nucleus of an atom can be modeled as several protons and neutrons closely packed together. Each particle has a mass of 1.67 ✕ 10−27 kg and radius on the order of 10−15 m. (a) Use this model and the data provided to estimate the density of the nucleus of an atom. kg/m3 (b) Compare your result with the density of a material such as iron (ρ = 7874 kg/m3). What do your result and comparison suggest about the structure of matter?Problem 5: Any ideal gas at standard temperature and pressure (STP) has a number density (atoms per unit volume) of p = N/V = 2.68 × 1025 m²3. How many atoms are there in 11 cubic micrometers, at STP? N =| atomsThe element neptunium has a density of 19.6 g/ml. What is the radius of a sphere of this material if it has a mass of 70kg? V=4/3pi r^3
- Growth of yeast cells In a controlled laboratory experiment, yeast cells are grown in an automated cell culture system that counts the number P of cells present at hourly intervals. The num- ber after t hours is shown in the accompanying figure. 250 200 150 100 50 0 1 2 3 4 5 6 7 a. Explain what is meant by the derivative P'(5). What are its units? b. Which is larger, P'(2) or P'(3)? Give a reason for your answer. c. The quadratic curve capturing the trend of the data points (see Section 1.4) is given by P(t) = 6.10r2 – 9.28t + 16.43. Find the instantaneous rate of growth when t = 5 hours.(a) Suppose a meter Stick made of steel and one made of invar (an alloy of iron and nickel) are the same length at 0C. What is their difference in length at 22.0C ? (b) Repeat the calculation for two 30.0mlong surveyor's tapes.Approximately how many atoms thick is a cell membrane, assuming all atoms there average about twice the size of a hydrogen atom?
