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9-1 (P) 2 2. Since the freezing point of a solution depends on the relative number of particles, what would you calculate to be the freezing point of 0.1 m solutions in water of (a) NaCl, (b) BaCl2? Assume that these salts are 100% ionized in solution. (Compare your answers with the actual respective freezing points: -0.348 °C and -0.470 °C. The difference is due to the decreased activity of the ions. Because of the attractive forces between the positively and negatively charged ions, they do not move completely independently of one another.) g- of 3. How m equ (a) (b) needed to give th

9-1 (P) 2 2. Since the freezing point of a solution depends on the relative number of particles, what would you calculate to be the freezing point of 0.1 m solutions in water of (a) NaCl, (b) BaCl2? Assume that these salts are 100% ionized in solution. (Compare your answers with the actual respective freezing points: -0.348 °C and -0.470 °C. The difference is due to the decreased activity of the ions. Because of the attractive forces between the positively and negatively charged ions, they do not move completely independently of one another.) g- of 3. How m equ (a) (b) needed to give th

General, Organic, and Biological Chemistry
General, Organic, and Biological Chemistry
7th Edition
ISBN:9781285853918
Author:H. Stephen Stoker
Publisher:H. Stephen Stoker
Chapter8: Solutions
Section: Chapter Questions
Problem 8.6EP: For each of the following pairs of solutions, select the solution for which solute solubility is...
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9-1 (P) 2 2. Since the freezing point of a solution depends on the relative number of particles, what would you calculate to be the freezing point of 0.1 m solutions in water of (a) NaCl, (b) BaCl2? Assume that these salts are 100% ionized in solution. (Compare your answers with the actual respective freezing points: -0.348 °C and -0.470 °C. The difference is due to the decreased activity of the ions. Because of the attractive forces between the positively and negatively charged ions, they do not move completely independently of one another.) g- of 3. How m equ (a) (b) needed to give th
Transcribed Image Text:9-1 (P) 2 2. Since the freezing point of a solution depends on the relative number of particles, what would you calculate to be the freezing point of 0.1 m solutions in water of (a) NaCl, (b) BaCl2? Assume that these salts are 100% ionized in solution. (Compare your answers with the actual respective freezing points: -0.348 °C and -0.470 °C. The difference is due to the decreased activity of the ions. Because of the attractive forces between the positively and negatively charged ions, they do not move completely independently of one another.) g- of 3. How m equ (a) (b) needed to give th
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