#9) The classic model for a parallel plate capacitor, has two plates separated by vacuum. Consider such a model capacitor, with plates separated by a distanced = 3 mm. Each plate carries a charge of magnitude 80 nC. With this plate spacing and charge distribution, an electric field of magnitude E = 4 x 10 V/m is developed across the plates. See the figure below. Answer the following questions, showing all work required to explain your answer(s): a) What is the potential difference developed between the two points a, and b?; b) Calculate the area, A, of each plate; c) Write the electric field in vector form, and show its direction in the figure below; and d) Calculate the capacitance of the parallel plate. Plate-a Qa =+80nC = - 80 n C Plate -b d=3 mm #10) For the capacitor described in problem #9, calculate the change in the properties calculated in #9, if a thin slab of the insulating compound SITIO3, i.e., strontium titanate (an insulating ceramic) were inserted snugly (in perfect electrical contact) between them plates. If certain quantities remain the same, be sure to mention it in your answer.

College Physics
10th Edition
ISBN:9781285737027
Author:Raymond A. Serway, Chris Vuille
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Chapter16: Electrical Energy And Capacitance
Section: Chapter Questions
Problem 5CQ: A parallel-plate capacitor with capacitance C0 stores charge of magnitude Q0 on plates of area A0...
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#9) The classic model for a parallel plate capacitor, has two plates separated by vacuum. Consider
such a model capacitor, with plates separated by a distanced = 3 mm. Each plate carries a charge
of magnitude 80 nC. With this plate spacing and charge distribution, an electric field of magnitude E
= 4 x 10 V/m is developed across the plates. See the figure below. Answer the following questions,
showing all work required to explain your answer(s):
a) What is the potential difference developed between the two points a, and b?;
b) Calculate the area, A, of each plate;
c) Write the electric field in vector form, and show its direction in the figure below; and
d) Calculate the capacitance of the parallel plate.
Plate-a
Qa =+80nC
= - 80 n C
Plate -b
d=3 mm
Transcribed Image Text:#9) The classic model for a parallel plate capacitor, has two plates separated by vacuum. Consider such a model capacitor, with plates separated by a distanced = 3 mm. Each plate carries a charge of magnitude 80 nC. With this plate spacing and charge distribution, an electric field of magnitude E = 4 x 10 V/m is developed across the plates. See the figure below. Answer the following questions, showing all work required to explain your answer(s): a) What is the potential difference developed between the two points a, and b?; b) Calculate the area, A, of each plate; c) Write the electric field in vector form, and show its direction in the figure below; and d) Calculate the capacitance of the parallel plate. Plate-a Qa =+80nC = - 80 n C Plate -b d=3 mm
#10) For the capacitor described in problem #9, calculate the change in the properties calculated in
#9, if a thin slab of the insulating compound SITIO3, i.e., strontium titanate (an insulating ceramic)
were inserted snugly (in perfect electrical contact) between them plates. If certain quantities remain
the same, be sure to mention it in your answer.
Transcribed Image Text:#10) For the capacitor described in problem #9, calculate the change in the properties calculated in #9, if a thin slab of the insulating compound SITIO3, i.e., strontium titanate (an insulating ceramic) were inserted snugly (in perfect electrical contact) between them plates. If certain quantities remain the same, be sure to mention it in your answer.
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