9. For hydroboration-oxidation, add the H and OH to the appropriate positions, with both regio and stereo considerations. A template is being provided, just add all groups to the appropriate positions – the Cl, Me groups, and Et group. Check your notes or pg. 2 above on whether hydroboration is a syn addition or anti addition. There is no one and only correct way to do this, but there is only one correct answer. Also, the enantiomer of each product you draw will also form. I'm only asking you to draw one of them. Et 1. ВН;, THF 1. ВНз, ТHF 2. Н2О2, NaOН -Me Н 2. H2O2, NaOH Me Me Me CI ....... The enantiomer will also form.

Organic Chemistry: A Guided Inquiry
2nd Edition
ISBN:9780618974122
Author:Andrei Straumanis
Publisher:Andrei Straumanis
Chapter21: Nas: Nucleophilic Aromatic Substitution
Section: Chapter Questions
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9. For hydroboration-oxidation, add the H and OH to the appropriate positions, with both regio and stereo
considerations. A template is being provided, just add all groups to the appropriate positions – the Cl, Me groups,
and Et group. Check your notes or pg. 2 above on whether hydroboration is a syn addition or anti addition. There
is no one and only correct way to do this, but there is only one correct answer. Also, the enantiomer of each
product you draw will also form. I'm only asking you to draw one of them.
Et
1. ВН;, THF
1. ВНз, ТHF
2. Н2О2, NaOН
-Me
Н
2. H2O2, NaOH
Me Me
Me
CI
.......
The enantiomer will also form.
Transcribed Image Text:9. For hydroboration-oxidation, add the H and OH to the appropriate positions, with both regio and stereo considerations. A template is being provided, just add all groups to the appropriate positions – the Cl, Me groups, and Et group. Check your notes or pg. 2 above on whether hydroboration is a syn addition or anti addition. There is no one and only correct way to do this, but there is only one correct answer. Also, the enantiomer of each product you draw will also form. I'm only asking you to draw one of them. Et 1. ВН;, THF 1. ВНз, ТHF 2. Н2О2, NaOН -Me Н 2. H2O2, NaOH Me Me Me CI ....... The enantiomer will also form.
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