1 Discontinuous Chips2Chemical stability or inertness3 Planning4Continuous chipsSeatbroachingCBNChip breakersMistelectrochemical machining10/10/25678Q1/A) Match between Column A & B.A910BA One type of application of cutting fluidsBTo support the insert (mechanical clamping type)CDuctile metals are cut at high speeds and relatively low depth of cutsCutting Tool Required PropertyDEVery high hardnessFNaCl or NaNO3GCutting time is quickHA straight & flat surface is createdI Eliminating long chipsJCast iron machined at low cutting speedAnswerfrom A

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A 1 Discontinuous Chips 2 Chemical stability or inertness 3 Planning Continuous chips Seat broaching CBN Chip breakers 9 Mist 10 electrochemical machining elin 4 5 6 7 8 A & B. B A One type of application of cutting fluids B To support the insert (mechanical clamping type) C D Ductile metals are cut at high speeds and relatively low depth of cuts Cutting Tool Required Property E Very high hardness NaCl or NaNO3 F G Cutting time is quick HA straight & flat surface is created I Eliminating long chips J Cast iron machined at low cutting speed Answer from A

A 1 Discontinuous Chips 2 Chemical stability or inertness 3 Planning Continuous chips Seat broaching CBN Chip breakers 9 Mist 10 electrochemical machining elin 4 5 6 7 8 A & B. B A One type of application of cutting fluids B To support the insert (mechanical clamping type) C D Ductile metals are cut at high speeds and relatively low depth of cuts Cutting Tool Required Property E Very high hardness NaCl or NaNO3 F G Cutting time is quick HA straight & flat surface is created I Eliminating long chips J Cast iron machined at low cutting speed Answer from A

Precision Machining Technology (MindTap Course List)

2nd Edition

ISBN:9781285444543

Author:Peter J. Hoffman, Eric S. Hopewell, Brian Janes

Publisher:Peter J. Hoffman, Eric S. Hopewell, Brian Janes

Chapter5: Turning

Section5.3: Machining Operations On The Lathe

Problem 5RQ: Calculate spindle RPM and machining time for cutting a 1.5" diameter 4" long at 225 SFPM using a...

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QL Match list (1) with list (IT) and select the correct answer? Ja] Type of chip 1 Continuous chip. 2 Serrated chips. List I List II Type of material being machined and the cutting conditions. A cast irons are machined at low cutting speeds B ductile materials at low-to-medium cutting speeds Ctitanium alloys machined at higher cutting speeds ductile work materials are cut at high speeds and relatively small feeds and depths 3 Discontinuous chip. Continuous chip with 4 built-up edges. D Types of Welds Geometry No. Flange weld A. 2 fillet weld 3 Surfacing weld 4 Plug weld D Slot weld 6 groove weld lel Process Grain flow of the part 1 Forging 2 Machining в 3 Casting
QUESTION 5 Determine the spindle speed (rpm), the feed rate (in/min) and the cutting power required for turning a 1º diameter copper rod with a depth of cut of 0.1" using a cemented carbide tool. O N=287 RPM, F-25.8 in/min, P=9.7 hp ON=2866 RPM, F=258 in/min, P=97 hp ON=1146 RPM, F-25.8 in/min, P=97 hp O N= 11460 RPM, F-340 in/min, P=130 hp ON= 1146 RPM, F-34 inimin, P= 13 hp ON= 115 RPM, F-3.4 in/min, P=1.3 hp QUESTION 6 It is required to face mill an aluminum block to size it down from 2" to 1.5" thick using a 3" diameter 2-toothed carbide cutting tool. The block is 6.0" wide and 6" long. The entire tool diameter engages the workpiece during the cut. Calculate the recommended spindle speed in revolutions per minute, feed per tooth, and cutting power required. O N=1529 RPM, f= 0.026 in/rev/tooth, P = 36 hp O N-3820 RPM, f= 26 in/revitooth, P=27 hp O N-3820 RPM, f= 0.052 in/rew/tooth, P=27 hp ON-382 RPM, F= 0.026 in/revitooth, P = 0.027 hp O N-3820 RPM, f= 0.052 in/rev/tooth, P=2.7 hp…
Write the NC part program for the part. Holes are threaded and requires two tools; T1 is a 0.5" HSS drill bit and T2 is a 0.5" tapping bit. The rest of the features are cut using a 0.75" HSS milling tool, T3. Feed rate and spindle speed are 10 ipm and 2000 rpm. The material is low- carbon steel. Part thickness is 0.5”. Use dotted lines two show the path of tools movements. Set up proper operation conditions as discussed in the class today.
13 Identify the type of milling operation in which the narrow slots or grooves can be produced into the workpiece. O peripheral milling out of O face milling question O slab milling O saw milling on 14 Cold working of metals will give better final properties than hot working. et ered Select one: ed out of O True O False ag question stion 15 In electroplating process the cathode is used to complete the circuit only and not for the coating of metals. Eyet 99+ Type here to search hp 144 14 10 * # %2$ % & 3 7 P E R G H K D F c v B NM . US 47
Identify the machining operation Profiling Facing Face Grooving Grooving
Q1/B) Match between Column A & B. A 1 Cutting Fluids 2 HSS 3 Serrated or segmented chips 4 Vertical shaper 5 Milling 6 Chip load 7 continuous Chip with BUE 8 Slitting 9 Electron beam machining 10 Ultrasonic machining B Horizontal milling machining vibration E Ductile material machined at low cutting speed F Interrupted cutting operation G Emulsified Oils H Cyclical formation of alternating high shear strain followed by low shear strain 1 Slotter J Feed per cutter tooth A Good toughness vacuum B C D Answer from A
Clear selection This is used tO correspond with machine tool usage where a working stroke would have high force capability at low speed and the return stroke could be rapid with no load O Grashof mechanism O Drag link mechanism O slider crank mechanism Quick return mechanism If two elements have theoretical surface contact with one another, then this element can be considered as:
The surface finish specification in a turning job is 0.90 um. The work material is cast iron. The cutting conditions have been selected as follows: v =90 m/min, f -0.23 mm/rev, and d = 2.2 mm. The nose radius of the cutting tool must be selected. Determine the minimum nose radius that will obtain the specified finish in this operation. oichie 0 90. m The wok matedal i material is
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a. If rough milling of mild steel is performed using High Speed Steel (HSS) side and face milling cutter of 100 mm diameter, what rpm should be used. b. If finish turning of a shaft is done to reduce its diameter from 24 mm to 20 mm using carbide tool, what rpm should be used. Metric Surface Speeds in m/min (Cutting Speed) Tool Material Aluminum Drilling Carbide 90 - 115 Milling - Rough Carbide Milling - Finish Carbide 120 - 240 Turning Carbide Rough Carbide Finish HSS HSS HSS 55 - 60 120 - 240 150 - 270 75 - 105 60 - 90 60 - 90 135 - 180 Brass 40 - 45 75 - 100 45 - 60 60 - 75 90 - 210 105 - 210 135 - 260 35 - 45 55 - 75 60 - 90 75 - 105 60 - 100 Cast Iron 12 - 18 15 - 25 25 - 30 60 - 90 75 - 135 Mild Steel 10 - 15 75 - 105 75 - 120 18 - 27 18 -3- 45 - 60 23 - 40 100 - 145 Stainless Steel 8 - 18 25 - 37 10 - 15 55 - 67 12 - 25 85 - 150
Standard time & work sampling The following data resulted from a time study made on a horizontal milling machine: Mean manual effort time per cycle: 4.62 min Mean cutting time (power feed): 3.74 min Mean performance rating: 115 percent Machine allowance (power feed): 10 percent Fatigue allowance: 15 percent questions: 1.) What is the Basic Time for the manual effort? 2.) What is the Standard Time for the manual effort? 3.) What is the Standard Time for the machine?
In machining operation, if velocity doubled then the 1ool life reduced to 1/16 th of initial value. Taylor's tool life index (n) for a machining operation is