A 1.20 kg object is subjected to three forces that give it an acceleration à = (4.80 m/s² )î + (5.00 m/s²). If two of the threeforces are F₁ = (28.0 N )i + (11.0 N ) and F₂ = (15.0 N )i + (8.00 N )ĵ, find (a) the x component and (b) the ycomponent of the the third force.

Calculate the total force on the object. F=maF=(1.20 kg)[(4.80 m/s2)i+(5.00 m/s2)j]F=(5.76 N)i+(6.00…

A 1.20 kg object is subjected to three forces that give it an acceleration à = (4.80 m/s² )î + (5.00 m/s² )}. If two of the three : F₁ = (28.0 N )î + (11.0 N )Ĵ and F₂ = (15.0 N )î + (8.00 N )ĵ, find (a) the x component and (b) the y component of the the third force.

A 1.20 kg object is subjected to three forces that give it an acceleration à = (4.80 m/s² )î + (5.00 m/s² )}. If two of the three : F₁ = (28.0 N )î + (11.0 N )Ĵ and F₂ = (15.0 N )î + (8.00 N )ĵ, find (a) the x component and (b) the y component of the the third force.

Principles of Physics: A Calculus-Based Text

5th Edition

ISBN:9781133104261

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter6: Energy Of A System

Section: Chapter Questions

Problem 8P

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Concept explainers

Rotational Equilibrium And Rotational Dynamics

In physics, the state of balance between the forces and the dynamics of motion is called the equilibrium state. The balance between various forces acting on a system in a rotational motion is called rotational equilibrium or rotational dynamics.

Equilibrium of Forces

The tension created on one body during push or pull is known as force.

Question

A 1.20 kg object is subjected to three forces that give it an acceleration à = (4.80 m/s² )î + (5.00 m/s²). If two of the three
forces are F₁ = (28.0 N )i + (11.0 N ) and F₂ = (15.0 N )i + (8.00 N )ĵ, find (a) the x component and (b) the y
component of the the third force.

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