A 5.4kg box is released on an incline as shown. The coefficient of kinetic friction is 0.22. Neglect drag. How many forces are acting on the box? What is the magnitude of the normal force? unit What is the magnitude of the friction? unit What is the magnitude of the net force? unit 31 What is the magnitude of box's acceleration? unit

icon
Related questions
Question
A 5.4kg box is released on an incline as shown. The coefficient of kinetic friction is
0.22. Neglect drag.
How many forces are acting on the box?
What is the magnitude of the normal force?
unit v
What is the magnitude of the friction?
unit
What is the magnitude of the net force?
unit
What is the magnitude of box's acceleration?
31...
unit
cannot be determined
check answers
e Forces, complete problems 2
entific Online Calculator
B1m/s?, vsound 343m/s
t 3 significant figures
1 PM
Rain to stop a GA
26/2022
OType here to search
1OC
VE = at
=-9.81x 3-20
-Vf= -31-39
t-3 20
340
dist=50
2
かで+9585
Transcribed Image Text:A 5.4kg box is released on an incline as shown. The coefficient of kinetic friction is 0.22. Neglect drag. How many forces are acting on the box? What is the magnitude of the normal force? unit v What is the magnitude of the friction? unit What is the magnitude of the net force? unit What is the magnitude of box's acceleration? 31... unit cannot be determined check answers e Forces, complete problems 2 entific Online Calculator B1m/s?, vsound 343m/s t 3 significant figures 1 PM Rain to stop a GA 26/2022 OType here to search 1OC VE = at =-9.81x 3-20 -Vf= -31-39 t-3 20 340 dist=50 2 かで+9585
Expert Solution
Step 1

The box having a mass of 5.4 kg is sliding on the incline, at an angle of 31 with the horizontal, where the incline has a coefficient of kinetic friction equal to 0.22.

Let m=5.4 kgμ=0.22θ=31°

As the box is sliding down the incline, there are a number of forces acting on the box.

First is the weight, or the gravitational force on the box, acting vertically downwards.

Next is the normal force acting on the box due to the surface of the incline, acting normal to this surface.

A force of friction between the box and the surface, as the box slides down, in a direction opposite to the direction of motion of the box on the plane.

And as a result of all these forces, a net force acts on the box, in the direction of motion of the box.

trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 4 steps

Blurred answer