ANSWER IN 20 MINS A 50.0 kN shipping container, initially at rest, is being pulled with forces P1 = 20.0 kN and P2 = 10.00 kN as shown in the figure. The coefficients of nonslidingfriction and sliding friction between the container and the ground is 0.400 and 0.300 respectively.3.00 m64.1 kN25.7 kN24.1 KN19.24 KNCqB2. Which of the following equilibrium equations is INCORRECT?3.00 mDA45.0°P₁ = 20.0 kNP2 = 10.00 KN1.000 mA: ΣFx = P₁ cos 45 + P₂ - f = 0B:ΣFy=N-W-P₁sin 45 = 0C: +UM₁ = W(1.5) – P₁ cos 45 (3) – P₁ sin 45 (3) – P₂(1) – Nx = 0D: + EMB = −W (1.5) – P₁ cos 45 (3) – P₁ sin 45 (3) − P₂(1) + N(3-x) = 03. Which of the following best approximates the maximum frictional resistance that can be developed between the container and the ground?

Answered: Image /qna-images/answer/b86f57ff-4b4e-40ec-9627-cd25598130ac.jpg

A 50.0 kN shipping container, initially at rest, is being pulled with forces P1 = 20.0 kN and P2 = 10.00 kN as shown in the figure. The coefficients of nonsliding friction and sliding friction between the container and the ground is 0.400 and 0.300 respectively. C 3.00 m 2. Which of the following equilibrium equations is INCORRECT? 64.1 kN 25.7 KN 24.1 kN 19.24 KN 3.00 m ◆ B q D A 45.0° P₁ = 20.0 kN A: EF = P₁ cos 45 + P₂ - f = 0 B: EF=N-W-P₁ sin 45 = 0 C: + EMA = W(1.5) – P₁ cos 45 (3) – P₁ sin 45 (3) - P₂(1) - Nx = 0 D: + EMB = −W (1.5) – P₁ cos 45 (3) – P₁ sin 45 (3) − P₂(1) + N(3 − x) = 0 3. Which of the following best approximates the maximum frictional resistance that can be developed between the container and the ground? P₂ = 10.00 kN 1.000 m

A 50.0 kN shipping container, initially at rest, is being pulled with forces P1 = 20.0 kN and P2 = 10.00 kN as shown in the figure. The coefficients of nonsliding friction and sliding friction between the container and the ground is 0.400 and 0.300 respectively. C 3.00 m 2. Which of the following equilibrium equations is INCORRECT? 64.1 kN 25.7 KN 24.1 kN 19.24 KN 3.00 m ◆ B q D A 45.0° P₁ = 20.0 kN A: EF = P₁ cos 45 + P₂ - f = 0 B: EF=N-W-P₁ sin 45 = 0 C: + EMA = W(1.5) – P₁ cos 45 (3) – P₁ sin 45 (3) - P₂(1) - Nx = 0 D: + EMB = −W (1.5) – P₁ cos 45 (3) – P₁ sin 45 (3) − P₂(1) + N(3 − x) = 0 3. Which of the following best approximates the maximum frictional resistance that can be developed between the container and the ground? P₂ = 10.00 kN 1.000 m

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

Note : point load = 12.289KN/m *3 = 36.867KN . 1) calculate the reaction forces 2) Calculate and draw the Bending moment digram, and what is the value of maximium bending moment ? 3) calculate and draw the shear force digram and what is the value of the maximum shear force ?
A roadway sign that weighs Py = 6 kN is supported by a structural pipe with an outside diameter of 335 mm and a wall thickness of 12.0 mm. Wind pressure on the sign creates a resultant force of P₂ = 21 kN, acting as shown. Using length dimensions of a = 5.2 m and b = 6.6 m, determine (a) the normal and shear stresses at point H. (b) the normal and shear stresses at point K. P₂ Py N b H y K a x
SITUATION. An 8-m long ladder weighing 900N is shown in the figure. It is required to determine the horizontal force P that must be exerted at point C to prevent the ladder from sliding. The coefficient of friction between the ladder and the surface at A and B is 0.20. W = 900 N 4m 4.59m 2 m 35° A, 6.55m Determine the reaction at A. 662.35 kN 1012.34 kN 487.89 kN 798.97 kN B. P.
The 12 kN crate is being pulled by the force P as shown in the figure. The force P makes an angle of e with the horizontal. a) Find the smallest possible force P to cause the crate to slide. b) Determine the angle e. c) Determine the horizontal frictional force acting at the bottom of the crate, W=12KN Note : The total surface R I Pmin - M= 0.20
Problem 1. Determine the minimum horizontal force P required to keep the crate from sliding down the incline (the crate will slide down if no force is applied). The crate has a mass of 50 kg and the coefficient of static friction between the crate and the incline is µs = 0.25. P 30°
A belt is passing over a fixed drum. If the magnitude of the force F is 2.5 kN, determine the angle 8 at which the 4-kN load will just begin to slip (the impending slip of the belt is in the clockwise direction) Assume that µ = 0.25. F = 2.5 kN 8-909 a 4 kN
Problem 9. For the tank shown in the figure, the following dimensions apply: h1=3.00m h2=4.50m w=2.50m y=9.81kN/m^3. Compute the horizontal component of the resultant force on the curved surfaces.a. 168.0 kNb. 158.0 kNc. 148.0 kNd. 138.0 kNe. 128.0 kNf. 118.0 kN
A weight weighing 15 Newtons starts on A, on top of a smoothing rolling mechanism with a velocity of 5 m/s. After passing through the mechanism, the crate will travel a distance d on a rough surface to B until it stops. The coefficient of kinetic friction is 0.4 N. Determine the distance d assuming a constant horizontal force of 21N (due to air resistance) is acting on the weight from the bottom of the mechanism to point B. A 5 m/s 1 m Hint: Use Vertical work
1. An overhang beam carries a uniform load of 3.2 KN/m as shown in the figure. Draw the shear and moment diagrams using the relationships of loads, shear and moment by area computation. 3.2 kN/m A C B 300 3.0 m 1.5 m
Perform double integration of the bending moment equations. You will obtain deflections in this form: UEI = F(x) + C₁x + C3 vEI = G(x) + C₂x + C4 for 0 ≤ x ≤a for a ≤x≤a+b Calculate: e) the value of the integration constant C₂. Enter your answer in kNm² to three decimal places.
3. A man slowly pushes on a 50-kg rectangular crate with a pushing force P of angle 30° downward. Knowing that the crate starts to tip about the edge of the loading dock when h=0.9m, determine (a) the smallest friction coefficient u between the crate and loading dock, (b) the magnitude P of the force. 1.2m P B 0.2m 30° h
A simple beam AB with a total length of 2.40 meters is subjected to a trapezoidal distributed load. The intensity of the load varies from 1.00 kN/m at support A to 3.00 kN/m at support B. What is the reaction at support A and B.What is the resultant applied load?What is the degree of shear-force equation?What is the value of shear force at x = 2.00 m from support A?What is the distance of absolute maximum bending moment from support B?What is the value of bending moment at x = 2.35m?What is the value of absolute maximum bending moment? What is the value of shear force at x = 1.80 m?