(a) A 60-kVA, 4800/2400-V single-phase transformer gave the following test results: Rated voltage is applied to the low voltage winding and the high voltage winding is open-circuited. Under this condition, the current flow into the low voltage winding is 2.4 A and the power taken from the 2400 V source is 3456 W. A reduced voltage of 1250 V was applied to the high voltage winding and the low voltage winding was short- circuited. Under this condition, the current flowing into the high voltage winding is 12.5 A and the power which is taken from the 1250 V source is 4375 W. Design the equivalent circuit referred to the high voltage side by considering: Open circuit test (ii) Shunt parameters referred to high voltage side (iii) Short circuit test

Power System Analysis and Design (MindTap Course List)
6th Edition
ISBN:9781305632134
Author:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma
Publisher:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma
Chapter3: Power Transformers
Section: Chapter Questions
Problem 3.9P
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(a)
A 60-kVA, 4800/2400-V single-phase transformer gave the following test results:
Rated voltage is applied to the low voltage winding and the high voltage winding is
open-circuited. Under this condition, the current flow into the low voltage winding is
2.4 A and the power taken from the 2400 V source is 3456 W. A reduced voltage of
1250 V was applied to the high voltage winding and the low voltage winding was short-
circuited. Under this condition, the current flowing into the high voltage winding is 12.5
A and the power which is taken from the 1250 V source is 4375 W. Design the
equivalent circuit referred to the high voltage side by considering:
(i)
Open circuit test
(ii)
Shunt parameters referred to high voltage side
(iii)
Short circuit test
Transcribed Image Text:(a) A 60-kVA, 4800/2400-V single-phase transformer gave the following test results: Rated voltage is applied to the low voltage winding and the high voltage winding is open-circuited. Under this condition, the current flow into the low voltage winding is 2.4 A and the power taken from the 2400 V source is 3456 W. A reduced voltage of 1250 V was applied to the high voltage winding and the low voltage winding was short- circuited. Under this condition, the current flowing into the high voltage winding is 12.5 A and the power which is taken from the 1250 V source is 4375 W. Design the equivalent circuit referred to the high voltage side by considering: (i) Open circuit test (ii) Shunt parameters referred to high voltage side (iii) Short circuit test
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