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Use the law of exponents on radicals
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Solved in 3 steps with 3 images
- 1. Expand and simplify. _/10K] а) (5m - 8)(3m - 2) b) (5х — 3)? с) (х +4)(х - 5) + 3(4х — 5)(х — 11)3 4 10 find -2 -5) 5 If A = 8 and B = 1 1) (а) (АВ)" (b) В'АТQuestion 3 Let P = 2ax + 5ay - 3az, Q = 3ax - 4ay, and R = ax + ay + az. Determine P + 2Q А) 8ах- Зау - 3az в) -5ах + Зау -Зaz c) 4ax + 2ay - 3az D) -Зах- 2аy + 4az
- Furthermore, Eq. (10) gives us U8n-5U8n-9 И8п-3 — U8n-5 + U8n-7 - Ugn-9 e2n c" 2n-1n-1 e2n c" + a"-1(c – e)" (a – c)" ап-1(с-е)п (а-с)п ап-1(а—с)п-1(с-е) -1 e2n-1cn-1 ап-1 (а—с)п—1(с-е)п-1 спе2n-1 an-1(c-e)n-1(a-c)n 2n c" e2n cn a"-1 (с — е)"(а — с)" e2n cn а" (с — е)" (а — с)т-т (음-) а — с (с — е)" (а — с)" e2n cn+1 a" (с — е)"(а — с)" an an Also, Eq. (10) leads to U8n-4u8n-8 U8n-2 = U8n-4 + U8n-6 U8n-8 f2n-1 an-1 fn-1(d-f)r(b-d)n bn-1(b-d)n-1(d-f)n-I f2n–1 dn-1 (b-d)n-1(d-f)n-I f2n dn f2n d" bn-1(d – f)"(b – d)" + dn f2n-1 bn-1(d-f)n–1(b-d)n hn f2n d" b* (d – f)"(b – d)n-1 f2n dn bn-1(d – f)"(b –- d)" f2m d" br (d – f)"(b – d)n f2n qn+1 b" (d – f)"(b – d)" 1 d)-1 Moreover, Eq. (10) gives U8n-3U8n-7 U8n-1 = U8n-3 + и8п-5 — и8n-7 cn+1e2n а" (а-с)" (с—е)" e2n cn ап-1(с-е)" (а-с)" c"2n-1 cn+le2n aп-1(с-е)m — 1(а-с)" а" (а — с)"(с — е)" che2n-1 aп-1(с-е)m —1(а-с)т an cn+1e2n c"e2n a" (а — с)"(с — е)" a" (с — е)"-1(а — с)" (1 + c-e n cn+1e2n c"e2n a" (а — с)" (с — е)" а" (с - е)п-1(а — с)п…5) 7) 9) -3x²y-3 -ух. 4у Su3 6-4 uv 6х³у2 -х². у ² -2 xx 11) 6) 8) бать". бь 6ba³ 3x'y -5x³y+-6x²y6 22 6x³.4xy6 Au'v-6.4v³ -5 -би 10) 12)а) 2х, -3х2 +5X3 -2 Хм = 9 5X2 +X3 +3X4 = 1 7Х3 - Хи = 3 2хч = 8 =