A ball of mass m, at one end of a string of length L, rotates in a vertical circle just fast enough to prevent the string from going slack at the top of the circle. The speed of the ball at the bottom of the circle is: A. √2gL B. √3gL C. √4gL D. √5gL E. √7gL L m O at the top #+mg = mxx² R V=JRg

Q: Given M = 31 +4ĵ - 5k and N = 61 - 4 ĵ - 4k, calculate the vector product M x Ñ. K Î + ĵ+

A: −36i+(−18)j+(−36)kExplanation:For any query with the solution, please ask in the comment box.

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A: The volume of the ring is 0.2004 cm3The density of the ring is 10.42 g/cm3Explanation:

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Q: î × ƒ = k‚ ƒ × k = î, k×î=j, A× B = -B × A, |Ã× B|= AB sin 0, FB = qv×B,H R = = mv ‚ FÅ = IL × B. qB…

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Q: Physics question help

A: The final answer is attached below Explanation:

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Centripetal Force

A particle, body, object or certain mass while travelling in a rotational path or semicircular path, experiences an inertia force. If that inertia force pulls the towards the inward of the imaginary circle in the rotation, it is termed as centripetal force.