A beam fixed at both ends, as shown in the Fig, has a F=20 kN concentrated load applied at the centre of the span. The beam structure is supported from the bottom, by a linear spring, with k=400 N/cm. In addition, the beam structure is a attached to the adjacent vertical walls through two truss elements, with cross-sectional area of A= 11.55 x10-3 cm². Calculate the lateral (vertical) deflection and slope at the middle (Note: Iz is the same as ). Take E= 20x106 N/cm?, for all elements, and I= 2500 cm4 1 2 3 4 12 EI 6 ΕΙ. 12 ΕΙ 6El , L 6 ΕΙ. L 6 EI L' 12 El L? 2Εl. 300 30° 4Εl. (1) E500 cm- (2) 500 cm [k] = L. 6EI 12 EI 6EI 3 L 6 EI L² 2 EI L 6EI L? 4 EI 4 L

Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
Section: Chapter Questions
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A beam fixed at both ends, as shown in the Fig, has a F=20 kN concentrated load applied at the
centre of the span. The beam structure is supported from the bottom, by a linear spring, with
k=400 N/cm. In addition, the beam structure is a attached to the adjacent vertical walls through
two truss elements, with cross-sectional area of A= 11.55 x10-3 cm².
Calculate the lateral (vertical) deflection and slope at the middle (Note: Iz is the same as ).
Take E= 20x106 N/cm?, for all elements, and I= 2500 cm4
1
2
3
4
12 EI
6 ΕΙ.
12 ΕΙ
6 ΕΙ.
L
6EI ,
L
6 EI
L
12 El
L'
6 EI
L?
2Εl.
300
30°
4Εl.
(1)
E500 cm-
(2)
500 cm
[k]=
L.
6EI
12 EI
6EI
3
L²
2 EI
L
6EI
4 EI
4
L
Transcribed Image Text:A beam fixed at both ends, as shown in the Fig, has a F=20 kN concentrated load applied at the centre of the span. The beam structure is supported from the bottom, by a linear spring, with k=400 N/cm. In addition, the beam structure is a attached to the adjacent vertical walls through two truss elements, with cross-sectional area of A= 11.55 x10-3 cm². Calculate the lateral (vertical) deflection and slope at the middle (Note: Iz is the same as ). Take E= 20x106 N/cm?, for all elements, and I= 2500 cm4 1 2 3 4 12 EI 6 ΕΙ. 12 ΕΙ 6 ΕΙ. L 6EI , L 6 EI L 12 El L' 6 EI L? 2Εl. 300 30° 4Εl. (1) E500 cm- (2) 500 cm [k]= L. 6EI 12 EI 6EI 3 L² 2 EI L 6EI 4 EI 4 L
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