A bicyclist started out traveling with a velocity of 2020 miles per hour. After 1515 minutes had passed, the bicyclist was traveling with a velocity of 2323 miles per hour. The formula for finding the acceleration of an object is change in velocitychange in time.change in velocitychange in time. What is the correct way to analyze the units for this situation?
A bicyclist started out traveling with a velocity of 2020 miles per hour. After 1515 minutes had passed, the bicyclist was traveling with a velocity of 2323 miles per hour. The formula for finding the acceleration of an object is change in velocitychange in time.change in velocitychange in time. What is the correct way to analyze the units for this situation?
College Physics
1st Edition
ISBN:9781938168000
Author:Paul Peter Urone, Roger Hinrichs
Publisher:Paul Peter Urone, Roger Hinrichs
Chapter1: Introduction: The Nature Of Science And Physics
Section: Chapter Questions
Problem 9PE: Tectonic plates are large segments of the Earth's crust that move slowly. Suppose that one such...
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A bicyclist started out traveling with a velocity of 2020 miles per hour. After 1515 minutes had passed, the bicyclist was traveling with a velocity of 2323 miles per hour. The formula for finding the acceleration of an object is change in velocitychange in time.change in velocitychange in time.
What is the correct way to analyze the units for this situation?
A.Convert the units for the given time from minutes to hours, so that the units for the change in velocity are mileshourmileshour and the units for the change in time are hours. When simplifying the fraction, the units become mileshour2.mileshour2.
Convert the units for the given time from minutes to hours, so that the units for the change in velocity are mileshourmileshour and the units for the change in time are hours. When simplifying the fraction, the units become mileshour2.mileshour2.
B.Leave the units for the given time as minutes, so that the units for the change in velocity are mileshourmileshour and the units for the change in time are minutes. When simplifying the fraction, the units become miles⋅minuteshour.miles⋅minuteshour.
Leave the units for the given time as minutes, so that the units for the change in velocity are mileshourmileshour and the units for the change in time are minutes. When simplifying the fraction, the units become miles⋅minuteshour.miles⋅minuteshour.
C.Leave the units for the given time as minutes, so that the units for the change in velocity are mileshourmileshour and the units for the change in time are hours. When simplifying the fraction, the time units cancel, leaving the unit miles.
Leave the units for the given time as minutes, so that the units for the change in velocity are mileshourmileshour and the units for the change in time are hours. When simplifying the fraction, the time units cancel, leaving the unit miles.
D.Convert the units for the given time from minutes to hours, so that the units for the change in velocity are mileshourmileshour and the units for the change in time are hours. When simplifying the fraction, the time units cancel, leaving the unit miles.
Convert the units for the given time from minutes to hours, so that the units for the change in velocity are mileshourmileshour and the units for the change in time are hours. When simplifying the fraction, the time units cancel, leaving the unit miles.
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