A block of mass m = 5.70 kg is attached to a light spring and slides on a rough horizontal surface as shown in the figure below. Thespring constant is k = 90.0 N/m and the coefficient of kinetic friction between the block and the surface is µy = 0.150. The block isreleased from rest when the spring is stretched the distance x; = 22.00 cm .wwwwx = 0x= x;(a) Find the work done by the friction force from the start of the motion to the moment when the block passes the equilibrium positionX = 0.W =(b) Find the speed of the ball when it passes the equilibrium position x = 0 .V =m/s(c) Find the position of the block xf, at which it will stop.Xf =cm

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Description: A block of mass m = 5.70 kg is attached to a light spring and slides on a rough horizontal surface as shown in the figure below. Thespring constant is k = 90.0 N/m and the coefficient of kinetic friction between the block and the surface is µy = 0.1

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A block of mass m = 5.70 kg is attached to a light spring and slides on a rough horizontal surface as shown in the figure below. The spring constant is k = 90.0 N/m and the coefficient of kinetic friction between the block and the surface is µy = 0.150 . The block is released from rest when the spring is stretched the distance x; = 22.00 cm . x= 0 x= X; (a) Find the work done by the friction force from the start of the motion to the moment when the block passes the equilibrium positior x = 0. W = (b) Find the speed of the ball when it passes the equilibrium position x = 0 . V = m/s (c) Find the position of the block xf, at which it will stop. Xf = cm

A block of mass m = 5.70 kg is attached to a light spring and slides on a rough horizontal surface as shown in the figure below. The spring constant is k = 90.0 N/m and the coefficient of kinetic friction between the block and the surface is µy = 0.150 . The block is released from rest when the spring is stretched the distance x; = 22.00 cm . x= 0 x= X; (a) Find the work done by the friction force from the start of the motion to the moment when the block passes the equilibrium positior x = 0. W = (b) Find the speed of the ball when it passes the equilibrium position x = 0 . V = m/s (c) Find the position of the block xf, at which it will stop. Xf = cm

Principles of Physics: A Calculus-Based Text

5th Edition

ISBN:9781133104261

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter7: Conservation Of Energy

Section: Chapter Questions

Problem 15P: A block of mass m = 2.00 kg is attached to a spring of force constant k = 500 N/m as shown in Figure...

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